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Nadusha1986 [10]
3 years ago
13

(2x^3)^2 x 6x^2 (2m^0 x 5m)^2 x 5m^2

Mathematics
1 answer:
Nana76 [90]3 years ago
8 0

Answer:

\large\boxed{(2x^3)^2\times6x^2=24x^8}

Step-by-step explanation:

(2x^3)^2\times6x^2\qquad\text{use}\ (ab)^n=a^nb^n\ \text{and}\ (a^n)^m=a^{nm}\\\\=2^2(x^3)^2\times6x^2=4x^6\times6x^2=(4\times6)(x^6x^2)\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=24x^{6+2}=24x^8

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3 0
3 years ago
Do the ratios 4/5 and 12/20 form a proportion?
yKpoI14uk [10]

Answer:

No. They are not in proportion

Step-by-step explanation:

\sf \dfrac{4}{5} \ \text{is in the simplest form}

\sf \text{Simplest form of $\dfrac{12}{20}$} = \dfrac{12 \div 4}{20 \div 4}=\dfrac{3}{5}

So, they are not in proportion

7 0
2 years ago
determine the length of side y, to the nearest tenth, in each of the following triangles. Please show work
umka21 [38]
The final answer is 10.9

6 0
3 years ago
NEED HELP ASAP
VARVARA [1.3K]

When solving an equation with an absolute value term, you make two separate equations ans solve for x:

Equation 1: |4x-3|-5 = 4

1st add 5 to both sides:

|4x-3| = 9

Remove the absolute value term and make two equations:

4x-3 = 9 and 4x - 3 = -9

Solving for x you get X = 3 and x = -1.5

When you replace x with those values in the original equation the statement is true so those are two solutions.

Do the same thing for equation 2:

|2x+3| +8 = 3

Subtract 8 from both sides:

|2x+3| = -5

Remove the absolute value term and make two equations:

2x +3 = -5

2x+3 = 5

Solving for x you get -1 and 4, but when you replace x in the original equation with those values, the statement is false, so there are no solutions.

The answer is:

C. The solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution.

3 0
3 years ago
Use cubic regression to find a function that fits the following points.
8090 [49]

Answer:

y = 2x³ + x² - 4x + 6

Step-by-step explanation:

General formula:

y = ax³ + bx² + cx + d

If you replace point (0, 6) in the general formula, you get:

6 = a(0)³ + b(0)² + c(0) + d

6 = d

If you replace points (-1, 9), (1, 5) and (2, 18) in the general formula, you get the following system of equations:

9 = a(-1)³ + b(-1)² + c(-1) + 6

9 = -a + b - c + 6     (eq. 1)

5 = a(1)³ + b(1)² + c(1) + 6

5 = a + b + c + 6     (eq. 2)

18 = a(2)³ + b(2)² + c(2) + d

18 = 8a + 4b + 2c + 6     (eq. 3)

Adding equation 1 to equation 2:

14 = 2b + 12

(14 - 12)/2 = b

b = 1

Multiplying equation 1 by 2:

18 = -2a + 2b - 2c + 12     (eq. 4)

Adding equation 4 to equation 3, and replacing with b value:

36 = 6a + 6b + 18

36 = 6a + 6 + 18

(36 - 6 - 18)/6 = a

a = 2

Replacing a and b values in equation 1:

9 = -2 + 1 - c + 6

c = -2 + 1 + 6  - 9

c = -4

8 0
3 years ago
Read 2 more answers
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