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jeka94
3 years ago
5

A boat can travel 2.30 m/s in still water. If the boat points its prow directly across a stream whose current is 1.80 m/s , what

is the magnitude of the velocity of the boat relative to the shore?
Physics
1 answer:
Alinara [238K]3 years ago
5 0

Answer:

A boat can travel 2.30 m/s in still water. (a) If the boat points its prow directly across a stream whose current is. ... (a) What is the velocity (magnitude and direction) of the boat relative to the shore? ... The boat's velocity with respect to the shore, , is the sum of its velocity with respect to the water

Explanation:

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1.
8_murik_8 [283]

Answer: 2.61 s

Explanation:

We are given the following data:

s=5 ft is the initial height of the object

v=40 ft/s is the initial height of the object

In addition, the motion of the object is given by:

h=-16t^{2}+ vt +s (1)

Where:

h=0 ft is the final height of the object

t is the time the object is in the air before hitting the ground

Rewritting (1) with the given data:

0=-16t^{2}+ 40t +5 (2)

Solving the quadratic equation with the quadratic formula t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}, where a=-16, b=40, c=5 and choosing the positive value of time:

t=\frac{-40\pm\sqrt{(-40)^{2}-4(-16)(5)}}{2(-16)} (3)

t=2.61 s (4) This is the time

5 0
3 years ago
Is it true or false that the displacement always equals the product of the average velocity and the time interval?
Cloud [144]

Answer:

True.

Explanation:

  • Applying the definition of average velocity, we know that we can always write the following expression:

        v_{avg} = \frac{\Delta x}{\Delta t} (1)

  • By definition, Δx is just the displacement, and Δt is the time interval.
  • So, just rearranging terms in (1), we get:

        \Delta x} = v_{avg}* {\Delta t}

5 0
3 years ago
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