Initial concentration of magnesium nitrate M1 = 2.13 M
Initial volume of magnesium nitrate, MgNO3 V1 = 1.24 L
Final concentration of MgNO3, M2 = 1.60 M
Let the final volume of MgNO3 upon dilution be V2
Formula to use:
M1*V1 = M2*V2
V2 = M1*V1/M2
= 2.13 M * 1.24 L/1.60 M = 1.65 L
Thus, the final volume of magnesium nitrate solution upon dilution is 1.65 L
Answer:
The splash cause the volume of the block to be too high
Explanation:
This is because, from the previous measurement made by the student, the volume of the block is 5.7ml higher.
Answer:
N2O(g) + 3 H2O(l) ---------------> 2 NH3(g) + 2 O2(g)
Explanation:
If we look at the reaction stated in the question, we will notice that the option chosen in the answer is the reverse of that reaction.
One thing is clear, if a reaction is possible, then its reverse reaction is equally possible. The equilibrium position may shift towards the forward or reverse reaction based on the conditions of the reaction.
Hence if the reaction, 2NH3(g) + 2O2(g) → N2O(g) + 3H2O(l) is possible, then the reaction, N2O(g) + 3 H2O(l) ---------------> 2 NH3(g) + 2 O2(g) is also possible.
Energy absorbed from
changing the phase of a substance from the liquid phase to gas phase can be
calculated by using the specific latent heat of vaporization. Calculation are
as follows:
<span> Energy = 1.35 mol CCl4 ( 153.81 g / 1 mol ) x 197.8 J/g </span>
<span>Energy = 41071.88 J</span>
Will refreact through the lens and diverge, never intersecting
