Answer:
1=4
2=2
3=hydrogen bonding
4=SO2 is reduced to Sulphur
Explanation:
<h2>I am trying my best okay.</h2>
Answer:
500 cubic centimeters of water
274 mL H3 O+ and fully neutralized
It will take one teaspoon of Mg(OH)2 to completely neutralize 2.00×10^2mL of H3O+.
<h3>What is the purpose of milk of magnesia?</h3>
- For a brief period of time, this medicine is used to relieve sporadic constipation.
- It is an osmotic laxative, which means that it works by drawing water into the intestines, which aids in causing bowel movement.
<h3>What dosage of milk of magnesia is recommended for constipation?</h3>
- Take Milk of Magnesia once day, preferably before bed, in divided doses, or as prescribed by a physician.
- suggested dosage: 30 mL to 60 mL for adults and kids 12 years of age and older. 15 mL to 30 mL for children aged 6 to 11 years.
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the question you are looking for is
People often take milk of magnesia to reduce the discomfort associated with acid stomach or heartburn. The recommended dose is 1 teaspoon, which contains 4.00x 10^{2} mg of Mg(OH)_2. What volume of an HCl solution with a pH of 1.3 can be neutralized by one dose of milk of magnesia? If the stomach contains 2.00x10^{2}mL of pH 1.3 solution, is all the acid neutralized? If not, what fraction is neutralized?
According to Coulomb's Law, as the atomic number increases within a series of atoms, the nuclear attraction for electrons will also increase, thus pulling the electron(s) closer to the nucleus.
Answer:
After 28 sec 7.5 grams of Be will be left
Explanation:
Given data:
Total amount of Be = 30 g
Half life of Be = 14 sec
Mass left after 28 sec = ?
Solution:
First of all we will calculate the number of half lives in 28 sec.
Number of half lives = T elapsed / half life
Number of half lives = 28 sec / 14 sec
Number of half lives = 2
AT time zero = 30 g
At first half life = 30 g/2 = 15 g
At second half life = 15 g/ 2 = 7.5 g
So after 28 sec 7.5 grams of Be will be left.
