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balu736 [363]
2 years ago
5

I need help with this

Chemistry
2 answers:
cricket20 [7]2 years ago
7 0

Answer:

#TEAM BOB

FOR BOB!!!!!!!

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Copy and paste to help Bob.

We can do it together!#TEAM BOB

FOR BOB!!!!!!!

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░░░░░░░▀███▀█░▄░░ Help Bob

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Copy and paste to help Bob.

We can do it together!#TEAM BOB

FOR BOB!!!!!!!

░░░░░▐▀█▀▌░░░░▀█▄░░░

░░░░░▐█▄█▌░░░░░░▀█▄░░

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░░░█▀▄▄▄█░▀▀░░

░░░▌░▄▄▄▐▌▀▀▀░░ Dis is Bob

▄░▐░░░▄▄░█░▀▀ ░░

▀█▌░░░▄░▀█▀░▀ ░░

░░░░░░░▄▄▐▌▄▄░░░

░░░░░░░▀███▀█░▄░░ Help Bob

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░░░░░░▐▀░░░░░░▐▌░░ brainly.

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Copy and paste to help Bob.

We can do it together!

Explanation:

Vedmedyk [2.9K]2 years ago
5 0

Answer:

i think its 63 pls do not get mad if not 63

Explanation:

from 60 you add three?(:

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What is the overall cell potential for this redox reaction? Ca2+ + 2Li = Ca + 2Li+ Ca2+ + 2e- = Ca -2.87 V Li = Li+ + e- -3.05 V
Jet001 [13]

The redox reaction is

Ca^{+2}  + 2Li(s)  = Ca(s) + 2Li^{+}

Here

Calcium undergoes reduction, and acts as cathode

Lithium undergoes oxidation and acts as anode

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