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vovangra [49]
3 years ago
11

X

Mathematics
1 answer:
12345 [234]3 years ago
3 0

Answer: 28.35\ minutes

Step-by-step explanation:

Let be "x" the time in minutes a 150-pound person must walk at  4 mph to use at least 190 calories.

 The amount of calories that a 150-pound person uses  in 1 minute when walking at a speed of 4 mph is:

Calories\ per\ minute=6.7

Therefore, knowing this, we can write the following proportion:

\frac{1}{6.7}=\frac{x}{190}

Finally, we must solve for "x" in order to find its value.

Multiplying both sides of the equation by 190, we get this result:

(190)(\frac{1}{6.7})=(\frac{x}{190})(190)\\\\x=28.35

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Use multiplication to find 2 equivalent fraction for 3/4 and 4/5
Contact [7]
Equivalent fractions for 3/4 are 6/8 and 9/12

Equivalent fractions for 4/5 is 8/10 and 12/15
7 0
3 years ago
Oliver is buying his new soccer uniform his jersey was $21.50 his cleats for $44.95 and his water bottle was $12 if you paid wit
Anon25 [30]

Answer:

$21.55

Step-by-step explanation:

21.50 + 44.95 + 12 = $78.45

100 - 78.45= $21.55

8 0
3 years ago
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lawyer [7]

Answer:

21/4 or 5.25

Step-by-step explanation:

3 0
3 years ago
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The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m
UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of \bar X Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

4 0
3 years ago
Help please. thank u :)
Sveta_85 [38]

Answer:

help

Step-by-step explanation:

5 0
3 years ago
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