Answer:
Object 3 has greatest acceleration.
Explanation:
Objects Mass Force
1 10 kg 4 N
2 100 grams 20 N
3 10 grams 4 N
4 1 kg 20 N
Acceleration of object 1,
Acceleration of object 2,
Acceleration of object 3,
Acceleration of object 4,
It is clear that the acceleration of object 3 is 
and it is greatest of all. So, the correct option is (3).
Answer:
Heya how have you been doing
Answer:
R = 715.4 N
L = 166.6 N
Explanation:
ASSUME the painter is standing right of center
Let L be the left rope tension
Let R be the right rope tension
Sum moments about the left end to zero. Assume CCW moment is positive
R[5] - 20(9.8)[5/2] - 70(9.8)[5/2 + 2] = 0
R = 715.4 N
Sum moments about the right end to zero
20(9.8)[5/2] + 70(9.8)[5/2 - 2] - L[5] = 0
L = 166.6 N
We can verify by summing vertical forces
116.6 + 715.4 - (70 + 20)(9.8) ?=? 0
0 = 0 checks
If the assumption about which side of center the paint stood is incorrect, the only difference would be the values of L and R would be swapped.
Answer:
80m/s
Explanation:
to find it you have to work it out by using the formula distance divided by speed to find time.
Answer:
5.77×10¹⁰ m
Explanation:
From the question,
Applying
Kepler's third law
P² = d³...................... Equation 1
Where P = Planet's period, d = distance between the center of the planet and the sun.
make d the subject of the formula n equation 1
d = ![\sqrt[3]{P^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7BP%5E%7B2%7D%20%20%7D)
.................. Equation 2
Given: P = 0.24 sidereal.
Substitute the value of P into equation 2
d = ![\sqrt[3]{0.24^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.24%5E%7B2%7D%20%7D)
d = 0.386 Au
d = 0.386×1.496×10¹¹
d = 5.77×10¹⁰ m
