Answer:
F = 3.6 x 10⁻²⁴ N
Explanation:
The force of attraction or repulsion between two charges is given by the Coulomb's Law. Coulomb's Law states that:
F = kq₁q₂/r²
where,
F = Electric Force between electrons = ?
k = Coulomb's Constant = 9 x 10⁹ N.m²/C²
q₁ = q₂ = Charge on electron = 1.6 x 10⁻¹⁹ C
r = distance between electrons = 0.8 cm = 0.008 m
Therefore,
F = (9 x 10⁹ N.m²/C²)(1.6 x 10⁻¹⁹ C)(1.6 x 10⁻¹⁹ C)/(0.008 m)²
<u>F = 3.6 x 10⁻²⁴ N</u>
Answer:
A) 7×10⁻⁸ N
Explanation:
r = Distance between the two skaters = 2 m
m₁ = m₂ = Mass of the two skaters = 65 kg
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
From Newton's Law of Universal gravity

∴ Force of gravity between the two skaters is 7×10⁻⁸ N
Answer:
Now e is due to the ring at a
So
We say
1/4πEo(ea/ a²+a²)^3/2
= 1/4πEo ea/2√2a³
So here E is faced towards the ring
Next is E due to a point at the centre
So
E² = 1/4πEo ( e/a²)
Finally we get the total
Et= E²-E
= e/4πEo(2√2-1/2√2)
So the direction here is away from the ring
The acceleration can be found by:

Where v= velocity and t= time
or