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Ahat [919]
4 years ago
15

2NaHCO, + Caci, -> Ca(OH), + 2NaCl +

Chemistry
1 answer:
Leto [7]4 years ago
4 0

Answer:

This is a precipitation reaction: Ca(OH)2 is the formed precipitate.

Reactants:

CaCl2 – Calcium chloride source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02

Other names: Calcium(II) chloride source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02, Calcium dichloride source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02, E509 source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02

Appearance: White powder, hygroscopic source: wikipedia, accessed: 2019-09-27; Odourless hygroscopic colourless or white crystals source: ICSC, accessed: 2019-09-04

NaOH

Names: Sodium hydroxide source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, Caustic soda source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, Lye source: wikidata, accessed: 2019-09-02

Appearance: White, waxy, opaque crystals source: wikipedia, accessed: 2019-09-27; White hygroscopic solid in various forms source: ICSC, accessed: 2019-09-04; Colorless to white, odorless solid (flakes, beads, granular form). source: NIOSH NPG, accessed: 2019-09-02

Products:

NaCl – Sodium chloride source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02

Other names: {{unbulleted list source: wikipedia, accessed: 2019-09-27, Salt source: wikidata, accessed: 2019-09-02, Table salt source: wikidata, accessed: 2019-09-02

Appearance: Colorless cubic crystals source: wikipedia, accessed: 2019-09-27

Ca(OH)2 – Calcium hydroxide source: wikipedia, accessed: 2019-09-28source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02

Other names: {{ubl source: wikipedia, accessed: 2019-09-28, Slaked lime source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, Calcium hydrate source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02

Appearance: White powder source: wikipedia, accessed: 2019-09-28; Colourless crystals or white powder source: ICSC, accessed: 2019-09-04; White, odorless powder. [Note: Readily absorbs CO2 from the air to form calcium carbonate.] source: NIOSH NPG, accessed: 2019-09-02

Explanation:

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0.254 M

Explanation:

If the formula mass of sugar is 342.3 g/mol, and there are 65.3 g, then there are 65.3/342.3=0.190768 mol.

Also, 750 mL = 0.750 L.

molarity = (moles of solute)/(liters of solution)

molarity = 0.190768/0.750 = <u>0.254</u><u> </u><u>M</u>

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A mixture of hydrochloric and sulfuric acids is prepared so that it contains 0.315 M HCl and 0.125 M H2SO4. What volume of 0.55
Xelga [282]

<u>Answer:</u> The volume of NaOH required is 402.9 mL

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}     .....(1)

  • <u>For HCl:</u>

Molarity of HCl solution = 0.315 M

Volume of solution = 503.4 mL = 0.5034 L   (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

0.315M=\frac{\text{Moles of HCl}}{0.5034L}\\\\\text{Moles of HCl}=(0.315mol/L\times 0.5034L)=0.1586mol

  • <u>For sulfuric acid:</u>

Molarity of sulfuric acid solution = 0.125 M

Volume of solution = 503.4 mL = 0.5034 L

Putting values in equation 1, we get:

0.125M=\frac{\text{Moles of }H_2SO_4}{0.5034L}\\\\\text{Moles of }H_2SO_4=(0.125mol/L\times 0.5034L)=0.0630mol

As, all of the acid is neutralized, so moles of NaOH = [0.1586 + 0.0630] moles = 0.2216 moles

Molarity of NaOH solution = 0.55 M

Moles of NaOH = 0.2216 moles

Putting values in equation 1, we get:

0.55M=\frac{0.2216}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.2216}{0.55}=0.4029L=402.9mL

Hence, the volume of NaOH required is 402.9 mL

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3 years ago
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