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Bingel [31]
3 years ago
12

How many moles of oxygen gas are necessary to completely react with 10.6 moles of propane? C3H8(g) + 5 O2(g) --> 3 CO2 (g) +

4 H2O (l)
Chemistry
1 answer:
blsea [12.9K]3 years ago
7 0

Answer:

53 moles of oxygen, O₂

Explanation:

The chemical equation for the reaction is presented as follows;

C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O (i)

From the above equation, 5 moles of oxygen, O₂, gas reacts completely with 1 mole of propane gas, C₃H₈

Therefore 10.6 × 5 = 53 moles of oxygen, O₂, will be required to react with 10.6 × 1 mole of propane, C₃H₈

The number of moles of oxygen, O₂, necessary to completely react with 10.6 moles of propane, C₃H₈ is 53 moles of oxygen, O₂

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The volume of the 0.15 M LiOH solution required to react with 50 mL of 0.4 M HCOOH to the equivalence point is 133.3 mL

<h3>Balanced equation </h3>

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From the balanced equation above,

The mole ratio of the acid, HCOOH (nA) = 1

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MaVa / MbVb = nA / nB

(0.4 × 50) / (0.15 × Vb) = 1

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0.15 × Vb = 20

Divide both side by 0.15

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Vb = 133.3 mL

Thus, the volume of the LiOH solution needed is 133.3 mL

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