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Bingel [31]
3 years ago
12

How many moles of oxygen gas are necessary to completely react with 10.6 moles of propane? C3H8(g) + 5 O2(g) --> 3 CO2 (g) +

4 H2O (l)
Chemistry
1 answer:
blsea [12.9K]3 years ago
7 0

Answer:

53 moles of oxygen, O₂

Explanation:

The chemical equation for the reaction is presented as follows;

C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O (i)

From the above equation, 5 moles of oxygen, O₂, gas reacts completely with 1 mole of propane gas, C₃H₈

Therefore 10.6 × 5 = 53 moles of oxygen, O₂, will be required to react with 10.6 × 1 mole of propane, C₃H₈

The number of moles of oxygen, O₂, necessary to completely react with 10.6 moles of propane, C₃H₈ is 53 moles of oxygen, O₂

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Deffense [45]
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v1=600, t1 =20c=293K
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3 years ago
Temperature cloud cover and thunder are all examples of
Umnica [9.8K]

Temperature, cloud cover and thunder are all examples of weather.  

<h3><u>Explanation:</u></h3>

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3 years ago
If the half-life of a radioactive element is 4 days, how long will it take for three- fourths of a sample of the element to deca
Jlenok [28]

Answer:

\boxed{\text{8 da}}

Explanation:

The question will be easier to solve if we interpret it as, " How long will it take until one-fourth of a sample of the element remains,?"

The half-life of the element is the time it takes for half of it to decay.  

After one half-life, half (50 %) of the original amount will remain.  

After a second half-life, half of that amount (25 %) will remain, and so on.  

We can construct a table as follows:

\begin{array}{cccl}\textbf{No. of} & & \textbf{Fraction} & \\\textbf{half-lives} & \textbf{t/da} & \textbf{remaining} & \\1 & 4 & \dfrac{1}{2} & \\\\2 & 8 & \dfrac{1}{4}& \\\\3 & 12 & \dfrac{1}{8}& \\\end{array}

\text{We see that 8 da is two half-lives, and the fraction of the element remaining is $\frac{1}{4}$.}\\\text{It takes $\boxed{\textbf{8 da}}$ for three-fourths of the element to decay}

3 0
3 years ago
How many grams of O are in 605 g of Na,O?
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Answer:

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156g of Na2O2 produces 32g of O2,

12g of Na2O2 produces =15632×12=10.66g.

Density of O2 at NTP=1.428g/mL.

DensityMass=Vol.

1.42810.66=7.46mL

Vol. of O2 at NTP is 7.46mL.

Explanation:

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The function of a specific enzyme is mostly determined by its
galben [10]

Answer:

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Explanation:

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