Answer:
6.4 L
Explanation:
When all other variables are held constant, you can use Boyle's Law to find the missing volume:
P₁V₁ = P₂V₂
In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the theoretical volume by plugging the given values into the equation and simplifying.
P₁ = 3.2 atm P₂ = 1.0 atm
V₁ = 2.0 L V₂ = ? L
P₁V₁ = P₂V₂ <----- Boyle's Law
(3.2 atm)(2.0 L) = (1.0 atm)V₂ <----- Insert values
6.4 = (1.0 atm)V₂ <----- Simplify left side
6.4 = V₂ <----- Divide both sides by 1.0
Answer:
Part 1. When the balloon is filled half of the way, and placed into the freezer, it will shrink. This happens because kinetic molecular theory tells us that a decrease in temperature decreases the kinetic energy of the gas molecules in the balloon. Viscous gases like hydrogen are less likely to shrink.
Part 2. When the balloon is placed out in the hot sun, most likely the balloon will swell and grow. This happens because the kinetic energy of the gas molecules increases due to solar radiation transforming into heat energy and then transforming into kinetic energy. Sticky gases like neon are more likely to grow.
Explanation:
Answer:
a.
△H=−72 kcal
The energy required for production of 1.6 g of glucose is [molecular mass of glucose is 180 gm]
b.
The iron(III) ions and chloride ions remain aqueous and are spectator ions in a reaction that produces solid barium sulfate.
<span>Answer is: the symbol is Cl.
[Ne ] 3s</span>² 3p⁶ is electric configuration of noble gas argon, neon (Ne) has10 electrons plus 6 electrons in 3s and 3p orbitals. Neutral atom of m<span>onatomic ion that has a charge of 1– has one electron less than argon, so that atom (chlorine) has 17 electrons. Charge of 1- means one electron more for ion: 17 + 1 = 18.
</span>
Answer:
<h2>0.06 % </h2>
Explanation:
The percentage error of a certain measurement can be found by using the formula
From the question
error = 500 - 499.7 = 0.3
actual volume = 500 mL
We have
We have the final answer as
<h3>0.06 % </h3>
Hope this helps you
