3. A 70 kg person climbs a 6 m ladder. How much work is required by the person?
1 answer:
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Explanation:
It is given that,
Uncertainty in the speed of an electron,
According to Heisenberg uncertainty principle,
is the uncertainty in the position of an electron
Since,
So, the uncertainty in its position is . Hence, this is the required solution.
Here , the density of the material is 4g cm³ but it is not given in CGS system.
$\sf{As\:we\:know\:that:}$
$\sf\bold{Density=}$ $\sf\dfrac{Mass}{Volume}$
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$\sf\small{Density\:of\:the\:material=4}$ $\sf\dfrac{g}{cm^2}$
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$\sf{It\:is\:given\:that:}$
In the system of units the mass is 100gram.
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Hence,
$\sf{The\:mass\:unit\:for\:4g=}$ $\sf\dfrac{4}{100}$ $\sf{units}$
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In the system of units,the length is 10cm.
Henceforth,
$\sf\small{The\:length \:for\:1cm\:units=}$ $\sf\dfrac{1}{10}$ $\sf{units}$
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<u>☆</u><u> </u><u>Substitute</u><u> </u><u>the</u><u> </u><u>required</u><u> </u><u>values</u><u> </u><u>in</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>formula</u><u>-</u>
$\sf\purple{Density=}$ $\sf\dfrac\purple{Mass}\purple{volume}$
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$\sf\underline\bold{Density\:of\:the\:material:}$
= $\sf\dfrac{4/100}{1/10^3}$ $\sf\bold{units}$
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= $\sf\dfrac{4/100}{1/1000}$ $\sf\bold{units}$
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= $\sf\dfrac{4000}{100}$ $\sf\bold{units}$
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$\sf\underline\bold\blue{=40\:units}$
$\sf\small{Therefore,option\:2nd\:is\:correct!}$
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