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jeyben [28]
3 years ago
8

3. A 70 kg person climbs a 6 m ladder. How much work is required by the person?

Physics
1 answer:
Lina20 [59]3 years ago
6 0

Answer:

4116J

Explanation:

Given parameters:

Mass of the person  = 70kg

Height of the ladder  = 6m

Unknown:

Work done  = ?

Solution:

The work done by the person climbing is the same as the potential energy.

Work done is the force applied to move a body through a distance;

So;

   Potential energy  = mass x acceleration due to gravity x height

Therefore;

    Potential energy  = 70 x 9.8 x 6   = 4116J

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Explanation:

The given data is as follows.

                    mass = 0.20 kg

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Now, we will calculate the total energy present present as follows.

         Total energy = Kinetic energy + spring potential energy

                           = 1.4 J + 2.2 J

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As maximum kinetic energy of the object will be equal to the total energy.

So,      K.E = Total energy

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or,                   v = \sqrt{\frac{2K.E}{m}}

                        = \sqrt{2 \times 3.6 J}{0.2 kg}

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A baseball has a mass of 0. 45 kg and is thrown with a speed of 25 m/s. What is the momentum of the baseball? 0. 018 kg • mete
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