Consider a magnesium wire (σ = 2.2 ✕ 107 Ω−1 · m−1) with a cross-sectional area of 1 mm2 (similar to your connecting wires) and
1 answer:
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Answer:
Newtons.
Explanation:
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
Where;
F represents force measured in Newton.
m represents the mass of an object measured in kilograms.
a represents acceleration measured in meter per seconds square.
Newtons is a measurement we use to determine the amount of force used to move an object by a simple machine. It is the International System of Units (SI) used to measure force and has a symbol of N.
Basically, it was named after Sir Isaac Newton based on his fundamental works in the field of mechanics (motions).
mass of the bottle in each case is M = 0.250 kg
now as per given speeds we can use the formula of kinetic energy to find it
1) when speed is 2 m/s
kinetic energy is given as
2) when speed is 3 m/s
kinetic energy is given as
3) when speed is 4 m/s
kinetic energy is given as
4) when speed is 5 m/s
kinetic energy is given as
5) when speed is 6 m/s
kinetic energy is given as
The rms speed of the molecules of gas A is twice that of gas B. The molecular mass of A is one fourth to that of B.
Answer: Option B
<u>Explanation:</u>
Measuring the speed of particles at a given point in time results in a large distribution of values. Some molecules can move very slowly, others very fast, and because they are still moving in different directions, the speeds may be zero. (Velocity, vector quantity that corresponds to the speed and direction of the molecule.)
To correctly estimate the average velocity, you must take the squares of the mean velocity and take the square root of this value. This is known as the root mean square (rms) velocity and is shown as follows:
Where,
M – Gas’s molar mass
R – Molar mass constant
T – Temperature (in Kelvin)
Given data is rms speed for gas molecule A is twice that of gas molecule B. So,
Therefore, equating the molecule’s rms speed formula for both A and B,
On squaring both sides, we get,
By solving the above equations, we get,