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Fed [463]
3 years ago
10

Consider a magnesium wire (σ = 2.2 ✕ 107 Ω−1 · m−1) with a cross-sectional area of 1 mm2 (similar to your connecting wires) and

carrying 0.3 amperes of current, which is about what you get in a circuit with a round bulb and two batteries in series. Calculate the strength of the very small electric field required to drive this current through the wire.
Physics
1 answer:
omeli [17]3 years ago
4 0

Answer: 1.36 x 10^-2 N/C

Explanation:

I/A = σ E

E = I / (A σ)

E = 0.3A / (1x10^-6 m^2 2.2 x10^7/ ohm m)

E = 1.36 x^-2 N/C

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