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tia_tia [17]
3 years ago
8

The amount of gravity between 1kg of lead and Earth is ___ the amount of gravity between 1kg of marshmallows and Earth.

Physics
1 answer:
Andrews [41]3 years ago
3 0

The amount of gravity between 1 kg of lead and Earth is the same as the amount of gravity between 1 kg of marshmallows and Earth.

Answer: Option C

<u>Explanation:</u>

According to universal law of gravity, the gravitational force is directly proportionate to the product of masses of the interacting objects and inversely proportionate to its distance squared between them.

Since the mass of Earth is very high compared to the mass of the other objects, be it lead or marshmallows, and the distance will be mostly same. Thus, there will be no change in the amount of gravity acting between them. Thus, the amount of gravity between 1 kg of lead and Earth is the same as the amount of gravity between 1 kg of marshmallows and Earth.

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The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.420 with the floor. If
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Answer:

The distance is  s=  30.3 \ m

Explanation:

From the question we are told that

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For the crate not to slide the friction force must be equal to the force acting on the train i.e

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The negative sign shows that the two forces are acting in opposite direction

=>   mg  *  \mu_s  =  ma

=>   -g  *  \mu_s  = a

=>   a =  -9.8 *  0.420

=>   a =  -4.116 m/s^2

From equation of motion

  v^2  = u^2  +  2as

Here  v =  0 m/s since it came to a stop

=>   s=  \frac{v^2 - u^2 }{ 2 a}

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To solve this problem it is only necessary to apply the kinematic equations of angular motion description, for this purpose we know by definition that,

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