1978 to 2004 is <em>26 years</em>.
Every 5.23 years, half of our 200-gram sample decays.
It has reached its half life ~4.97 times.
We use this formula to find our new amount:
Every time it reaches its half life, it will be halved...the fractional exponent there is to pick up minute differences like in our 4.97.
Answer:
10.87 g of Ethyl Butyrate
Solution:
The Balance Chemical Equation is as follow,
H₃C-CH₂-CH₂-COOH + H₃C-CH₂-OH → H₃C-CH₂-CH₂-COO-CH₂-CH₃ + H₂O
According to equation,
88.11 g (1 mol) Butanoic Acid produces = 116.16 g (1 mol) Ethyl Butyrate
So,
8.25 g Butanoic Acid will produce = X g of Ethyl Butyrate
Solving for X,
X = (8.25 g × 116.16 g) ÷ 88.11 g
X = 10.87 g of Ethyl Butyrate
The answer is leucine would be in the interior, and serine would be on the exterior of the globular protein.
The side chain (R group) of the amino acid serine is CH₂OH. The side chain of the amino acid leucine is CH₂CH(CH₃)₂. In globular protein, leucine found in the interior, and serine found on the exterior. The nature of side chain decides the amino acid position in the globular protein , as CH₂CH(CH₃)₂ this is hydrophobic and CH₂OH is hydrophlic.
Ep = mass x gravitational field strength (9.8N/kg) x height
Ep = 36 kg x 9.8 x 2m
Ep = 705.6 J
Answer: C. Acts as energy reserve in muscle tissue.
Explanation:
Creatine Phosphate is a high energy compound that can be found in muscle tissue.
It serves as an extra energy storage, since the normal metabolism cannot supply the high energy requirement of a muscle at work.
Creatine Phosphate is quickly transfered to ADP, for the production of ATP needed for muscle contraction.