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Nady [450]
2 years ago
11

What are easy ways toStudy Chemistry ??​

Chemistry
1 answer:
Elina [12.6K]2 years ago
7 0

Answer:

seneca

past papers

take notes from videos

Explanation:

very good website, asks questions about the subject correct for your exam board and gives correct answers and explanations

exam papers always help

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Need these 2 answered asap pls
Kitty [74]

Answer:

im not a brain wiz but i think 20

Explanation:

3 0
2 years ago
A 34.53 ml sample of a solution of sulfuric acid, h2s04, reacts with 27.86 ml of 0.08964 m naoh solution. calculate the molarity
Gnoma [55]
The balanced equation between NaOH and H₂SO₄ is as follows
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of moles of NaOH moles reacted = molarity of NaOH x volume
number of NaOH moles = 0.08964 mol/L x 27.86 x 10⁻³ L = 2.497 x 10⁻³ mol
according to molar ratio of 2:1
2 mol of NaOH reacts with 1 mol of H₂SO₄
therefore 2.497 x 10⁻³ mol of NaOH reacts with - 1/2 x 2.497 x 10⁻³ mol of H₂SO₄
number of moles of H₂SO₄ reacted - 1.249 x 10⁻³ mol 
Number of H₂SO₄ moles in 34.53 mL - 1.249 x 10⁻³ mol 
number of H₂SO₄ moles in 1000 mL - 1.249 x 10⁻³ mol / 34.53 x 10⁻³ L = 0.03617 mol 
molarity of H₂SO₄ is 0.03617 M
6 0
3 years ago
Can sedimentation and decantation be used for all types of mixtures? Explain
Bumek [7]

Explanation:

1. Sedimentation and decantation cannot be used for all types of mixtures.

Decantation is a separation technique in which is used to separate immiscible liquids or mixtures containing liquid and solids within them.

In decantation, gravity is used to bring the denser materials to settle at the bottom.

For homogenous mixtures, it is not possible to use decantation. A solution of sugar and water will not decant.

2. Yes, mass of an object reduces the settling time of such object in a mixture.

The higher the mass, the faster the rate of settling. Also, as we know, mass is directly proportional to density. A body with a high density will settle faster in solution.

4 0
3 years ago
What volume of 0.350 m koh is required to react completely with 24.0 ml of 0.650 m h3po4?
BartSMP [9]

The complete balanced chemical equation for this is:

<span>3KOH  +  H3PO4  -->  K3PO4  +  3H2O</span>

 

First we calculate the number of moles of H3PO4:

moles H3PO4 = 0.650 moles / L * 0.024 L = 0.0156 mol

 

From stoichiometry, 3 moles of KOH is required for every mole of H3PO4, therefore:

moles KOH = 0.0156 mol H3PO4 * (3 moles KOH / 1 mole H3PO4) = 0.0468 mol

 

Calculating for volume given molarity of 0.350 M KOH:

Volume = 0.0468 mol / (0.350 mol / L) = 0.1337 L = 133.7 mL

 

Answer:

<span>133.7 mL KOH</span>

7 0
3 years ago
Suggest type of bonding present in methane
Gre4nikov [31]
Sub to my youtube channel YaBoi El plsss
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3 years ago
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