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kompoz [17]
3 years ago
15

An atom of 14 6 c carbon decays by gamma decay which atom is left after the decay

Chemistry
2 answers:
ladessa [460]3 years ago
7 0
Answer is: carbon.

<span>During gamma emission the nucleus emits radiation without changing its composition, if for example have nucleus with six protons and six neutrons (carbon atom) and after gamma decay there is nucleus with six protons and six neutrons.
Gamma rays are the electromagnetic waves with the shortest wavelengths (1 pm), highest frequencies (300 EHz) and highest energy (1,24 MeV).</span>


WARRIOR [948]3 years ago
6 0

14/6C APEX your welcome

You might be interested in
5.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 7
slega [8]

Answer:

The molecular formula = C6H6

Explanation:

Step 1: Data given

Mass of compound X = 5.00 grams

Mass of products =

  CO2 = 16.39 grams

  H2O = 3.46 grams

Molar mass CO2 = 44.01 g/mol

Molar mass H2O = 18.02 g/mol

Molar mass C = 12.01 g/mol

Molar mass H = 1.01 g/mol

Molar mass O = 16. 0g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles CO2 = 16.93 grams / 44.01 g/mol

Moles CO2 =  0.385 moles

Moles C = 1* 0.385 = 0.385 moles

Moles H2O = 3.46 grams / 18.02

Moles H2O = 0.192 moles

Moles H = 2* 0.192 = 0.384 moles

Step 3: Calculate mass

Mass = moles * molar mass

Mass C = 0.385 moles *12.0 g/mol

Mass C = 4.62 grams

Mass H = 0.39 grams

Mass O = 5.00 - 4.62 -0.38 moles

Mass O = 0 grams

Step 4: Calculate mol ratio

We divide by the smallest amount of moles

C: 0.385 moles / 0.384 = 1

H: 0.384 moles / 0.384 = 1

The empirical formula is CH

This molecular formula is 13 g/mol

We have to multiply the empirical formula by n

n = 78 g/mol / 13 g/mol

n = 6

The molecular formula = 6*(CH) = C6H6

4 0
3 years ago
HELP ASAP!!! How many grams of lead are in a 41.2 gram sample of lead (II) oxide? With work please :)
Afina-wow [57]
That would be 58.6 oxide because if the 41.2 plus the oxide would be 48 plus the other particcles inside it so it equaled 58.6 oxide

5 0
3 years ago
Recovery standards are a necessary tool for determining exactly how much of a particular analyte you are able to extract from a
Dafna11 [192]

Answer:

2.05mg Fe/ g sample

Explanation:

In all chemical extractions you lose analyte. Recovery standards are a way to know how many analyte you lose.

In the problem you recover 3.5mg Fe / 1.0101g sample: <em>3.465mg Fe / g sample. </em>As real concentration of the standard is 4.0 mg / g of sample the percent of recovery extraction is:

3.465 / 4×100 = <em>86,6%</em>

As the recovery of your sample was 1.7mg Fe / 0.9582g, the Iron present in your sample is:

1.7mg Fe / 0.9582g sample× (100/86.6) = <em>2.05mg Fe / g sample</em>

<em></em>

I hope it helps!

5 0
3 years ago
Which term refers to compounds with the same molecular formula but different structural formulas?
GREYUIT [131]

Answer:

Isomers

I hope this helps :)))

6 0
3 years ago
Air resistance depends upon _____.
Sedaia [141]

Answer:

ye its b

Explanation:

6 0
2 years ago
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