To calculate amount accrued after a given period of time we use the compound interest formula: A= P(1+r/100)∧n where A i the amount, P is the principal amount, r is the rate of interest and n is the interest period.
In the first part; A= $ 675.54, r= 1.25% (compounded semi-annually) and n =22 ( 11 years ), hence, 675.54 = P( 1.0125)∧22
= 675.54= 1.314P
P= $ 514.109 , therefore the principal amount was $ 514 (to nearest dollar)
Part 2
principal amount (p)= $ 541, rate (r) = 1.2 % (compounded twice a year thus rate for one half will be 2.4/2) and the interest period (n)= 34 (17 years×2)
Amount= 541 (1.012)∧34
= 541 ×1.5
= $ 811.5
Therefore, the account balance after $ 811.5.
Answer:
Step-by-step explanation:
CArnival:E,D,B CATACOMBS:A,C,F
Using the information given we will only need the Cosine and Sine equations. i made a diagram (cant take a picture, in my study hall) labeled the sides of the triangle A, B, and C. with C as the hypotenuse, A as the Opposite, and B as the adjacent (will not be needed as A is the height). i will be rounding the th nearest thousandth.
Using Sine (SIN=Opposite/Hypotenuse), we can find A.
SIN(33)=A/4.4
SIN(33)≈.545
.545≈A/4.4
now multiply each side by 4.4 to get rid of the division
(.545*4.4)≈((A/4.4)4.4)
2.396≈A
so the answer would be that the slide is about 2.396 M high
Answer:
1/6
Step-by-step explanation:
should be the answer if I'm not mistaken
