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zheka24 [161]
3 years ago
8

Y-4=-3(x-3) in standard form

Mathematics
1 answer:
Stels [109]3 years ago
4 0

Answer:3x+y=13

Step-by-step explanation:

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This is what I need to know
I am Lyosha [343]
\bf \begin{array}{ccllll}
\$&minutes\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
920,000&46,000,000\\
x&1
\end{array}\implies \cfrac{920,000}{1}=\cfrac{46,000,000}{x}
so solve for "x", to see how much is the company paying for the purchase of 1 minute

now, they're plan to sell the minute for 8cents, how much is the profit?
that is, the difference from their cost of the cents to the planned selling price.

bear in mind, is 46,000,000 minutes, so whatever value you get for 1minute,
you need to multiply it for 46,000,000 to get the actual cost.

and the revenue from the sell of 8cents per minute, is of course, 8 * 46,000,000

profit = revenue - cost
7 0
3 years ago
Stefan buys a melon and divided into six servings he eat one third of the melon over the weekend how many slices of melon does S
kozerog [31]
2 slices of watermelon. He divides it into 6 slices and 1/3 of 6 is 2m
4 0
3 years ago
Suppose a couple planned to have three children. Let X be the number of girls the couple has.
sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

c)

P(X=2) = \dfrac{3}{8}

d)

P(\text{3 boys}) = \dfrac{1}{8}

Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

P(X=2)

That is we have to compute the probability that couple has exactly two girls.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

Favorable outcome: {GGB, GBG, BGG}

P(X=2) =\dfrac{3}{8}

d) probability that the couple have three boys.

Favorable outcome: {BBB}

P(BBB) = \dfrac{1}{8}

8 0
3 years ago
A number increased by two thirds of the number
Artyom0805 [142]

Answer:

not sure if you're looking for an example of this or not but if you are then it could be something like 12 + 8 because 2/3 of 12 is 8.

3 0
3 years ago
I'm so lost with this math problem
TEA [102]

Answer:

A: 1/5

B: 3/5

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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