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Virty [35]
3 years ago
7

Much like its household namesake, a molecular sieve utilizes differences in what property of substances to separate the componen

ts of mixtures?
A
freezing point

B
particle size

C
solubility

D
density
Chemistry
1 answer:
nlexa [21]3 years ago
4 0

Answer: B . particle size

Explanation:

Let's begin by explaining that a molecular sieve is a device, whose composition allows the absorbtion of molecules that are small enough to pass through its pores, since it is made up of small pores of a precise and uniform size.

Thus, very small molecules manage to pass through the pores of the sieve, while large ones do not.

So, based on this premise, a molecular sieve separates the substances by their size.

Hence, the correct option is B.

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33. Why does Fluorine exert a stronger pull than Chlorine on the valence electrons of another
mariarad [96]

Answer:

Fluorine is much more reactive than chlorine (despite the lower electron affinity) because the energy released in other steps in its reactions more than makes up for the lower amount of energy released as electron affinity.

Explanation:

7 0
2 years ago
What is the heat of fusion of water in calories per mole?​
Mumz [18]

Answer:

<u><em>79.72 Calories</em></u>

Explanation:

6 0
2 years ago
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Question 5
pantera1 [17]

Answer: The coefficient for the diatomic oxygen (O2) is 3.

Explanation:

To know the coefficient for the diatomic Oxygen, we need to balance the equation.

Fe + O2 ------->   Fe2O3

LHS of the equation; Fe =  1    , O2 = 1

RHS of the equation; Fe = 2 ,  O = 3

∴ Multiply 'Fe' on the LHS of the equation by 4 and O2 by 3

   Doing that will give the balance equation which is;

   4 Fe +  3 O2  --------> 2 Fe2O3

The coefficient for the diatomic oxygen (O2) as seen from the equation is 3.

7 0
3 years ago
Atoms of the element beryllium would most likely behave similar to the way _______ behaves.
lubasha [3.4K]
It's b. calcium 
because the outer electron structure in all of that element is similar, they have the same chemical and physical properties.<span />
3 0
3 years ago
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How many grams of oxygen are required to react with 13.0 grams of octane (C8H18) in the combustion of octane in gasoline?
egoroff_w [7]

Grams of oxygen are required to react with 13.0 grams of octane (C8H18) in the combustion of octane in gasoline is 45.5g

Octane is a hydrocarbon which burns in gasoline in presence of oxygen according to the given balanced chemical equation,

2C₈H₁₈ + 25O₂------> 16CO₂ + 18H₂0

Molar mass of octane = 114.23g/mol

Molar mass of Oxygen = 32g/mol

According to the stiochiometry of the balanced equation the mole ratio of Octane and Oxygen is 2:25

2 mole of octane needs 25 mole of oxygen

1 mole of octane needs 12.5 moleof oxygen

114.23g of octane needs 400g of oxygen

13g   of octane  needs 45.5g of oxygen

Mass of oxygen needed =45.5g

Hence, the Mass of oxygen needed is 45.5g for the combustion of octane in gasoline.

Learn more about Octane here, brainly.com/question/21268869

#SPJ4

5 0
2 years ago
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