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artcher [175]
3 years ago
12

Write an expression for the apparent nth term(a) of the sequence. 2,5,8,11,14...

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
7 0

Answer:

Step-by-step explanation:

Since the sequence is increasing by a constant factor (3) each time, we know that this is an arithmetic sequence.

The formula for an arithmetic sequence is the following:

a_{n} = a_{1} + (n - 1)d

Where n is the number in the sequence and d is the constant that the sequence is increasing by.

Based on all of the information given, we know that a_{1} = 2 (since 2 is the first number in the sequence), and d = 3, so we can construct the formula:

a_{n} = 2 + (n - 1)3

a_{n} = 2 + 3n - 3

a_{n} = 3n - 1

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Use the modle to find 2x137
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What should be done to both sides of the equation in order to solve y + 8.5 = 17.2?
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Answer:

Subtract 8.5

Step-by-step explanation:

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A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,
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We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation A=45e^{-0.05t}.

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate A=15 and solve for t as:

15=45e^{-0.05t}

\frac{15}{45}=\frac{45e^{-0.05t}}{45}

\frac{1}{3}=e^{-0.05t}

Now we will switch sides:

e^{-0.05t}=\frac{1}{3}

Let us take natural log on both sides of equation.

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Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})

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-0.05t=\text{ln}(\frac{1}{3})

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t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}

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Therefore, it will take 20\text{ln}(3) years for area of the glacier to decrease to 15 square kilo-meters.

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3 years ago
carols bikes 1 kilometer east 4 kilometers north and then 5 kilometers east again. how far is caroll from her starting position
Volgvan
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The distance traveled from Carol's starting point, along the path described, is
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