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2 years ago

What is needed for work to be done?

Chemistry

2 answers:

Shalnov [3]2 years ago

6 0

Answer: A force must cause an object to move along the same direction as the force.

Explanation:

Work is defined as displacement in the position of an object due to action of force. Mathematically the work done is a product of force and displacement of an object. The direction of the force applied and direction in which object is displaced is always same.

$Work=Force\times Displacement$

When work is done,a force must cause an object to move along the same direction as the force.

andrey2020 [161]2 years ago

3 0

For work to be done, a force must cause an object to move along the same direction as the force.
Hope this helps|!

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Please help!! What is this

ehidna [41]

Answer: It's a redox reaction

Explanation:

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3 years ago

Which option is a valid hypothesis in the correct format?

Rashid [163]

Answer:

4. If cotton plants need a consistent amount of water to grow steadily, then a cotton plant that displays steady growth will receieve 100 mL of water every day.

Explanation:

Hypotheses are written in the format of "If... then...". It should include information on both variables to arrive at a conclusion point.

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2 years ago

What is the correct IUPAC name for S2F8?

notka56 [123]

Answer:

Question: What Is The Correct IUPAC Name For S2F8? X ( ( (I) (IV) Di- Mono- Penta- Tetra- Tri- Hepta- Octa- Hexa- Fluorine Selenide Flourate Sulfide Sodium Sulfate Sulfur Fluoride Hydrate Acid.

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3 years ago

Determine the theoretical yield of HCl if 60.0 g of BC13 and 37.5 g of H20 are reacted according to the following balanced react

Pie

Answer : The theoretical yield of HCl is, 56.1735 grams

Explanation : Given,

Mass of $BCl_3$ = 60 g

Mass of $H_2O$ = 37.5 g

Molar mass of $BCl_3$ = 117 g/mole

Molar mass of $H_2O$ = 18 g/mole

Molar mass of $HCl$ = 36.5 g/mole

First we have to calculate the moles of $BCl_3$ and $H_2O$ .

$\text{Moles of }BCl_3=\frac{\text{Mass of }BCl_3}{\text{Molar mass of }BCl_3}=\frac{60g}{117g/mole}=0.513moles$

$\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{37.5g}{18g/mole}=2.083moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$BCl_3(g)+3H_2O(l)\rightarrow H_3BO_3(s)+3HCl(g)$

From the balanced reaction we conclude that

As, 1 mole of $BCl_3$ react with 3 mole of $H_2O$

So, 0.513 moles of $BCl_3$ react with $3\times 0.513=1.539$ moles of $H_2O$

From this we conclude that, $H_2O$ is an excess reagent because the given moles are greater than the required moles and $BCl_3$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $HCl$ .

As, 1 mole of $BCl_3$ react to give 3 moles of $HCl$

So, 0.513 moles of $BCl_3$ react to give $3\times 0.513=1.539$ moles of $HCl$

Now we have to calculate the mass of $HCl$ .

$\text{Mass of }HCl=\text{Moles of }HCl\times \text{Molar mass of }HCl$

$\text{Mass of }HCl=(1.539mole)\times (36.5g/mole)=56.1735g$

Therefore, the theoretical yield of HCl is, 56.1735 grams

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3 years ago

What is a magnetic reversal

Brilliant_brown [7]

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2 years ago