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Fantom [35]
2 years ago
8

When's the moon at its brightest? (QUICK!)

Chemistry
2 answers:
liberstina [14]2 years ago
8 0

Answer:

full moon i beleive if this is right would greatly apprecitate brainliest.      

Explanation:

erastovalidia [21]2 years ago
5 0

Answer:

around march

Explanation:

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Which two elements are in the same period?A. hydrogen (H) and neon (Ne)B. tin (Sn) and antimony (Sb)C. fluorine (F) and chlorine
ArbitrLikvidat [17]

Answer:

C. fluorine (F) and chlorine (Cl)

D. arsenic (As) and antimony (Sb)

Explanation:

In the periodic table , all the elements are arranged according to the atomic number ,

and the elements are placed in groups and periods ,

The elements with similar chemical and physical properties are placed in a common group .

The elements present in the same group have the same number of valence electrons in the valence shell  .

Hence , from the given options ,

fluorine (F) and chlorine (Cl)  belongs to group 17 with 7 valence electrons in the outermost shell .

arsenic (As) and antimony (Sb) belong to group 15 with 3 valence electrons in the outermost shell .

8 0
3 years ago
Question 3
stepladder [879]

This must be your work, otherwise it's against the Brainly code of conduct. If you need help finding a newspaper, go to BBC. They have plenty of relevant articles.

4 0
1 year ago
ANSWER<br> d is the corresect answer
loris [4]

Answer:

d is the correct answer

Explanation:

7 0
2 years ago
A 0.211 g sample of carbon dioxide, CO2, has a volume of 560 mL and a pressure of 429 mmHg whats the temperature of the gas in K
SCORPION-xisa [38]

The temperature of the gas sample is 813 K.

<u>Explanation:</u>

We have to use the ideal gas equation to find the temperature of the gas sample.

The ideal gas equation is PV = nRT

Pressure, P = 429 mm Hg = 0.56 atm

Volume, V = 560 mL = 0.56 L

R = gas constant = 0.08205 L atm mol⁻¹K⁻¹

Mass = 0.211 g

Molar mass of carbon di oxide = 44.01 g / mol

Moles, n = $\frac{given mass}{molar mass} = \frac{0.211 g}{44.01 g/mol}

              = 0.0047 mol

Now, we have to plugin the above values in the above equation, we will get the temperature as,

$T= \frac{PV}{nR}

T = $\frac{0.56  \times 0.56}{0.08205 \times 0.0047}

 = 813 K

So the temperature of the gas sample is 813 K.

5 0
3 years ago
A sample of nitrogen occupies 1.00L at a temperature of 250.k. What volume would it occupy at 1500.k?
11111nata11111 [884]
Your answer to the question is 6.
3 0
2 years ago
Read 2 more answers
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