FIRST MODEL: Well the model for the value of the house is:

V = Value
t = Years passed {t≥0}
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When t=0, V=120000
When t=1, V=132000
When t=2, V=145200
etc... etc...
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Now, this model is actually curved so there is no constant rate of growth each month. We can only calculate what the rate of growth is at a particular time. If we want to find out the rate of growth at a particular time, we must differentiate the formula (model) above.
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Plug any value of (t) that is greater than 0 into the formula above to find out how quickly the investment is growing. If you want to find out how quickly the investment was growing after 1 month had passed, transform t into 1/12.
The rate of growth is being measured in years, not months. So when t=1/12, the rate of growth turns out to be 11528.42 per annum.
SECOND MODEL (What you are ultimately looking for):
V = Value of house
t = months that have gone by {t≥0}
Formula above differentiated:






When t=1, dV/dt = 960.70 (2dp)
dV/dt in this case will measure the rate of growth monthly. As more money is accumulated, this rate of growth will rise. The rate of growth is constantly increasing as the graph of V is actually a curve. You can only find out the rate at which the house value is growing monthly at a particular time.
Answer:The area of a square is equal to the length of one side squared. Since the square root of 36 is 6, the length of 1 side is 6.
Step-by-step explanation:
Answer: 5x
Step-by-step explanation:
5x + 3x = 8x
Answer:

Step-by-step explanation:
You need to subtract the coefficients to get the answer.
Let's look at the equation...

The coefficient is 3 and 1
So, you do 3-1
You get 2
So...
I would think you would have to walk the 4 spaces out on the X axis. I would then turn and walk 5 spaces on the Z axis before turning up to walk the last 3 steps on the Y axis.
I think any other way would cause you to move in a negative direction. I hope this helps.