I am attaching a picture cause I cannot write it directly
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The answer is Condensing or condensation.
Using PV = nRT, we can calculate the moles of the sample.
874 mmHg = 116,524 Pa
n = PV/RT
n = 116,524 x 294 x 10⁻⁶ / 8.314 x (140 + 273)
n = 9.98 x 10⁻³ mol
moles = mass / Mr
Mr = 0.271/9.98 x 10⁻³
Mr = 27.2
Mass of empirical formula = 14
Repeat units = 27.2 / 14 ≈ 2
Formula of substance:
C₂H₄
Combustion equation:
C₂H₄ + 3O₂ → 2CO₂ + 2H₂O
1 mole produces 2 moles of CO₂, so 3 moles will produce 6 moles CO₂
Answer:
It takes 1,068.76 grams of nitrogen to fill an 855 L tank at STP.
Explanation:
The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C or 273.15 °K are used and are reference values for gases.
On the other side, the pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P*V = n*R*T
where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.
So, in this case:
- P= 1 atm
- V= 855 L
- n= ?
- R= 0.082
![\frac{atm*L}{mol*K}](https://tex.z-dn.net/?f=%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D)
- T= 273.15 K
Replacing:
1 atm* 855 L= n* 0.082
* 273.15 K
Solving:
![n=\frac{1 atm* 855 L}{0.082\frac{atm*L}{mol*K} *273.15 K }](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B1%20atm%2A%20855%20L%7D%7B0.082%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%20%2A273.15%20K%20%7D)
n= 38.17 moles
Being the molar mass of nitrogen N2 equal to 28 g / mol, you can apply the following rule of three: if there are 28 grams in 1 mole, how much mass is there in 38.17 moles?
![mass=\frac{38.17 moles*28 grams}{1 mole}](https://tex.z-dn.net/?f=mass%3D%5Cfrac%7B38.17%20moles%2A28%20grams%7D%7B1%20mole%7D)
mass= 1,068.76 grams
<u><em>
It takes 1,068.76 grams of nitrogen to fill an 855 L tank at STP.</em></u>
B.
The cynobacteria were already there without the oxygen, so that rules out A, and a lot of prokaryotes were anaerobic, so that rules out C. Finally, Photosynthesis does not require oxygen. Instead, Oxygen is a waste product of it. Therefore, it cannot be D. So, we are only left with B
Hoped this helped :D