Wavelength relates to frequency as follows: λ=vf in which f is the frequency, v is the speed of light, and λ is the wavelength.
Given:
No of atoms present= 8.022 x 10^23 atoms
Now we know that 1 mole= 6.022 x 10^23 atoms
Hence number of moles present in 8.022 x 10^23 atoms is calculated as below.
Number of moles
= 8.022 x 10^23/6.022x 10^23
=1.3 moles.
Hence we have 1.3 moles present.
Answer:
HF is the limiting reactant
Explanation:
The balanced equation for the reaction is given below:
SiO₂ + 4HF —> SiF₄ + 2H₂O
From the balanced equation above,
1 mole of SiO₂ reacted with 4 moles of HF.
Finally, we shall determine the limiting reactant. This can be obtained as illustrated below:
From the balanced equation above,
1 mole of SiO₂ reacted with 4 moles of HF.
Therefore, 7.5 moles of SiO₂ will react with = 7.5 × 4 = 30 moles of HF.
From the calculation made above, we can see clearly that it will take a higher amount (i.e 30 moles) of HF than what was given from the question (i.e 5 moles) to react completely with 7.5 moles of SiO₂.
Therefore, HF is the limiting reactant and SiO₂ is the excess reactant.
Answer:
Kc = 6x10⁻⁶
Explanation:
For the reaction:
4NH₃(g) + 3O₂(g) ⇄ 2N₂(g) + 6H₂O(g)
Kc is defined as:
Kc =[N₂]² [H₂O]⁶ / [NH₃]⁴ [O₂]³
The equilibrium concentrations of the gases is -Because volume of the container is 1.00L-:
[N₂] = 2X = 1.96x10⁻³; <em>X = 9.8x10⁻⁴</em>
[H₂O] = 6X; 6ₓ9.8x10⁻⁴ = 5.88x10⁻³
[NH₃] = 0.0150M - 4X = 0.01108M
[O₂] = 0.0150M - 3X = 0.01206M
Replacing in Kc expression:
Kc =[1.96x10⁻³]² [5.88x10⁻³]⁶ / [0.01108M]⁴ [0.01206M]³
<h3>Kc = 6x10⁻⁶</h3>
The electron configuration for Sodium (Na) is [Ne] 3s1
