Answer: I think that the answer was False.
Answer:
![H^+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_2O_{(l)}](https://tex.z-dn.net/?f=H%5E%2B_%7B%28aq%29%7D%2BOH%5E%7B-%7D_%7B%28aq%29%7D%5Crightarrow%20H_2O_%7B%28l%29%7D)
Explanation:
Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.
Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.
Only the species which are present in aqueous state dissociate.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
(a)
The balanced molecular equation will be,
The complete ionic equation in separated aqueous solution will be,
In this equation the species present are,
are the spectator ions.
Hence, the net ionic equation contains specie is
![H^+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_2O_{(l)}](https://tex.z-dn.net/?f=H%5E%2B_%7B%28aq%29%7D%2BOH%5E%7B-%7D_%7B%28aq%29%7D%5Crightarrow%20H_2O_%7B%28l%29%7D)
Answer:
![P_4_{(I)}+5O_2_{(g)}+6H_2O_{(l)}\rightarrow +4H_3PO_4_{(l)}](https://tex.z-dn.net/?f=P_4_%7B%28I%29%7D%2B5O_2_%7B%28g%29%7D%2B6H_2O_%7B%28l%29%7D%5Crightarrow%20%2B4H_3PO_4_%7B%28l%29%7D)
Explanation:
The first step is:
![P_4_{(I)}+5O_2_{(g)}\rightarrow 2P_2O_5_{(g)}](https://tex.z-dn.net/?f=P_4_%7B%28I%29%7D%2B5O_2_%7B%28g%29%7D%5Crightarrow%202P_2O_5_%7B%28g%29%7D)
Second step is:
![P_2O_5_{(g)}+3H_2O_{(l)}\rightarrow 2H_3PO_4_{(l)}](https://tex.z-dn.net/?f=P_2O_5_%7B%28g%29%7D%2B3H_2O_%7B%28l%29%7D%5Crightarrow%202H_3PO_4_%7B%28l%29%7D)
Multiplying second step by 2, and adding both the steps, we get that:
![P_4_{(I)}+5O_2_{(g)}+2P_2O_5_{(g)}+6H_2O_{(l)}\rightarrow 2P_2O_5_{(g)}+4H_3PO_4_{(l)}](https://tex.z-dn.net/?f=P_4_%7B%28I%29%7D%2B5O_2_%7B%28g%29%7D%2B2P_2O_5_%7B%28g%29%7D%2B6H_2O_%7B%28l%29%7D%5Crightarrow%202P_2O_5_%7B%28g%29%7D%2B4H_3PO_4_%7B%28l%29%7D)
Cancelling common species, we get that:
![P_4_{(l)}+5O_2_{(g)}+6H_2O_{(l)}\rightarrow +4H_3PO_4_{(l)}](https://tex.z-dn.net/?f=P_4_%7B%28l%29%7D%2B5O_2_%7B%28g%29%7D%2B6H_2O_%7B%28l%29%7D%5Crightarrow%20%2B4H_3PO_4_%7B%28l%29%7D)