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deff fn [24]
3 years ago
7

Which two surfaces would have the highest coefficient of friction?

Physics
2 answers:
scoray [572]3 years ago
5 0
<span>1. sandpaper against wood. 
2. rubber mat against the floor of the shower stall.

</span><span># High coefficient of friction describes the degree of interaction between two surfaces. . A higher coefficient of friction indicates that two surfaces in contact have a greater resistance.</span>
Natasha_Volkova [10]3 years ago
3 0

Answer:

rubber against dry concrete

Explanation:

apex

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What must difference between the atom of two different elements
Ksivusya [100]
A particular atom<span> will have the same number of protons and electrons and most</span>atoms<span> have at least as many neutrons as protons. An </span>element<span> is a substance that is made entirely from one type of </span>atom<span>. For example, the </span>element<span> hydrogen is made from </span>atoms<span> containing just one proton and one electron.

Hope this helps</span>
8 0
3 years ago
If a rock climber accidentally drops a 52.5-g piton from a height of 325 meters, what would its speed be just before striking th
alex41 [277]
Ignoring air resistance, the Kinetic energy before hitting the ground will be equal to the potential energy of the Piton at the top of the rock.  
So we have 1/2 MV^2 = MGH 
V^2 = 2GH 
V = âš2GH 
V = âš( 2 * 9.8 * 325)  
V = âš 6370
 V = 79.81 m/s
6 0
3 years ago
Which would be heavier—A ball of lead with a diameter of 2.00 cm or a cylinder of iron with a diameter of 3.00 cm and height of
Nana76 [90]

Explanation:

i think a ball of lead with a diameter of 2.00 cm heavier

4 0
3 years ago
What is the current in a 120 volt circuit if the resistance 5 ohms?
Lera25 [3.4K]

By Ohm's law:

  • V = IR

→ 120 = I(5)

→ I = (120/5)

→ I = 24 Ampere

<em>Hence, Option c) is correct </em>

4 0
3 years ago
YO
snow_tiger [21]

Hi there!

We can begin by calculating the distance remaining after the reaction time.

Δd = vt

Calculate the distance traveled within this time:

Δd = (16)(.79) = 12.64 m

Subtract from the total distance:

150 - 12.64 = 137.66 m remaining

We can use the following equation to solve for the acceleration necessary:

vf² = vi² + 2ad, where vf = 0 since the train will have slowed down to rest.

Rearrange in terms of "a":

0 = vi² + 2ad

(-vi²) = 2ad

(-vi²)/2d = a

Plug in the given values:

(-(16²))/2(137.66) = a

-256/275.32 = -.9298 m/s²

3 0
3 years ago
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