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melisa1 [442]
3 years ago
6

What do we measure energy in

Physics
2 answers:
olga2289 [7]3 years ago
5 0

We measure energy in joules

Goshia [24]3 years ago
3 0
Energy is measured by joule(j)
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Place a small object on the number line below at the position marked zero. Draw a circle around the object. Mark the center of t
Viefleur [7K]
It’s is D bc it is and idk you should do it
6 0
3 years ago
1.)how is climate different from weather
Zolol [24]
(sorry I can only answer no. 1)
the climate is the weather over a long period of time (could be days, weeks, months, or years) while weather is only how the day has been on one day (e.g. sunny)
6 0
3 years ago
7) Sound waves travel with a nominal speed of 340m/s.
Savatey [412]

Answer:

The wavelengths of C1 is 10.4m, A6 is 0.193m and B7 is 0.0861m

Explanation:

Using the formula V = f×λ . Then substitute the following values into the formula:

a) v=340m/s

f=32.7 Hz

λ=V ÷ f

= 340 ÷ 32.7

= 10.4m (3s.f)

b) λ=340 ÷ 1760

= 0.193m (3s.f)

c) λ=340÷3951.1

= 0.0861m (3s.f)

(Correct me if I am wrong)

4 0
2 years ago
The photon energies used in different types of medical x-ray imaging vary widely, depending upon the application. Single dental
Alchen [17]

1. Single dental x-rays: 5.0\cdot 10^{-11}m

The energy of the photon is

E=25 keV = 25,000 eV

Using the conversion factor

1 eV=1.6\cdot 10^{-19} J

we can convert it into Joules:

E=(25,000 eV)(1.6\cdot 10^{-19}J/eV)=4\cdot 10^{-15} J

The relationship between photon energy and wavelength is

\lambda=\frac{hc}{E}

where

h=6.63\cdot 10^{-34} Js is the Planck constant

c=3\cdot 10^8 m/s is the speed of light

E is the energy

Substituting into the formula, we find

\lambda=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{4\cdot 10^{-15} J}=5.0\cdot 10^{-11}m

2. Microtomography: 2.0\cdot 10^{-11} m

The energy of these photons is 2.5 times greater, so

E=(2.5)(4\cdot 10^{-15} J)=1\cdot 10^{-14} J

And by applying the same formula used at point 1, we find the corresponding wavelength:

\lambda=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{1\cdot 10^{-14} J}=2.0\cdot 10^{-11}m

6 0
3 years ago
A 94.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity of 44.0 m/s. If both are initially at rest and if t
miss Akunina [59]

Answer:

0.026 meter

Explanation:

using distance time equation to determine the time for the puck to move 16.5 meters.

distance 'd' = velocity'v' x time't'

16.5 = 44 x t    

t =0.375 second

Here momentum is conserved. Since both objects are initially at rest, the initial momentum is 0.

Next is to determine the puck’s momentum.

Momemtum 'p' = m x v => 0.15 x 44 = 6.6kg⋅m/s

The player momentum is -6.6kg⋅m/s  .

In order to determine the player’s velocity, we'll use p=mv

-6.6 = 94v

v= -0.0702 m/s

The above negative sign represents that the player is moving in the opposite direction of the puck.

Lastly, how far does the player recoil in the time it takes the puck to reach the goal 16.5 m away?

d = v x t = 0.0702 x 0.375= 0.026 meter

6 0
2 years ago
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