Answer: a. both reliable and valid
The parameters used to describe a particular trait or characteristic in a human behavior should be reliable and valid, in order to determine the response of the population with respect to a particular stimulus.
Answer:
x = 4.32 [m]
Explanation:
We must divide this problem into three parts, in the first part we must use Newton's second law which tells us that the force is equal to the product of mass by acceleration.
∑F = m*a
where:
F = force = 700 [N]
m = mass = 2030 [kg]
a = acceleration [m/s²]
Now replacing:
![F=m*a\\700=2030*a\\a = 0.344[m/s^{2}]](https://tex.z-dn.net/?f=F%3Dm%2Aa%5C%5C700%3D2030%2Aa%5C%5Ca%20%3D%200.344%5Bm%2Fs%5E%7B2%7D%5D)
Then we can determine the final speed using the principle of conservation of momentum and amount of movement.

where:
m₁ = mass of the car = 2030 [kg]
v₁ = velocity at the initial moment = 0 (the car starts from rest)
Imp₁₋₂ = The impulse or momentum (force by the time)
v₂ = final velocity after the impulse [m/s]
![(2030*0) + (700*5)=(2030*v_{2})\\3500 = 2030*v_{2}\\v_{2}=1.72[m/s]](https://tex.z-dn.net/?f=%282030%2A0%29%20%2B%20%28700%2A5%29%3D%282030%2Av_%7B2%7D%29%5C%5C3500%20%3D%202030%2Av_%7B2%7D%5C%5Cv_%7B2%7D%3D1.72%5Bm%2Fs%5D)
Now using the following equation of kinematics, we can determine the distance traveled.

where:
v₂ = final velocity = 1.72 [m/s]
v₁ = initial velocity = 0
a = acceleration = 0.344 [m/s²]
x = distance [m]
![1.72^{2}=0^{2} +(2*0.344*x) \\2.97 = 0.688*x\\x = 4.32 [m]](https://tex.z-dn.net/?f=1.72%5E%7B2%7D%3D0%5E%7B2%7D%20%2B%282%2A0.344%2Ax%29%20%5C%5C2.97%20%3D%200.688%2Ax%5C%5Cx%20%3D%204.32%20%5Bm%5D)
Answer:
Options A, B as well as C are the correct choices.
Explanation:
- Collaborative learning seems to be a circumstance where learning is an educational approach as well as make an effort to understand all this together.
- Except for personal learning, people participating in this learning draw mostly on competencies and qualifications of each other.
This form of learning isn't always linked to the perhaps one given choice. And the response to the above will still be the appropriate one.
Answer:
The force will be "9.8 N".
Explanation:
The given values are:
mass,
m = 0.7 kg
M = 2
g = 9.8
Now,
⇒ 
then,
⇒ 
⇒ 
⇒ 
On substituting the values, we get
⇒ 
⇒ 
hence,
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 
⇒ 
The kinetic energy (KE) of a 0.155 kg arrow that is shot from ground level, upward at 31.4 m/s, when it is 30.0 m above the ground is 30.85 J
Assuming air friction is negligible,
a = - 9.8 m / s²
u = 31.4 m / s
s = 30 m
v² = u² + 2 a s
v² = 31.4² + ( 2 * - 9.8 * 30 )
v² = 985.96 - 588
v² = 397.96 m / s
KE = 1 / 2 m v²
KE = 1 / 2 * 0.155 * 397.96
KE = 0.0775 * 397.96
KE = 30.85 J
Therefore, the kinetic energy ( KE ) when it is 30.0 m above the ground is 30.85 J
To know more about kinetic energy
brainly.com/question/24360064
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