Answer:
Explanation:
The capacitance of a parallel-plate capacitor is given by the formula:
where k is the dielectric constant of the material between them, A the area of the plates, d the distance between them and the permittivity, an universal constant.
Since the area of the plates is the product of their sides a=4.3cm=0.043m and b=4.2cm=0.042m, in S.I. we have:
Answer:
Not sure which statements were give to you for this question, but the vehicle's acceleration from noon to 2:00 PM was <em>zero</em>, the vehicle had a <em>positive</em> acceleration between 2:00 pm and 3:00 pm, and the vehicle had a <em>negative</em> acceleration at 4:30 PM.
Explanation:
From 12:00 PM to 2:00 PM, the vehicle traveled at a constant velocity of 70 MPH, meaning there wasn't any change to the speed. The velocity <em>remained the same</em>. An hour later, the velocity of the vehicle <em>increased</em> to 80 MPH, and finally at 4:30 PM, the velocity of the car <em>decreased </em>and was at 40 MPH.
Answer:
Explanation:
The question relates to Doppler effect and beat.
The observer is moving towards the reflected sound so apparent frequency will be increased
f = f₀ x (V + v₁) / (V - v₂)
f is apparent frequency , f₀ is real frequency , V is velocity of sound , v₁ is velocity of observer and v₂ is velocity of source . Here
v₁ = v₂ = vp as both observer and source have same velocity
f = f₀ x (V + v₁) / (V - v₂)
205 +5 = 205 x (344 +vp)/ ( 344 - vp)
1.0234 = (344 +vp)/ ( 344 - vp)
= 352 - 1.0234vp = 340+vp
12 / 2.0234vp
vp = 6 m /s approx.
The period T of a pendulum is given by:
where L is the length of the pendulum while
is the gravitational acceleration.
In the pendulum of the problem, one complete vibration takes exactly 0.200 s, this means its period is
. Using this data, we can solve the previous formula to find L:
Answer:
speed is -20.0155 m/s
and direction is downward
Explanation:
given data
mass of rocket = 1500 kg
rocket accelerates upward = 10 m/s²
time t = 2 s
maximum height = 530 m
to find out
speed and direction of the heavier fragment just after the explosion
solution
we use here principle of conservation of momentum that is
Mt Vt=M1 V1 + M2 V2 ................1
so here
first we find the initial velocity that is express as
v = a × t .....................2
v = 10 × 2
v = 20 m/s
and distance S
S =u × t + 0.5 × a × t² ...................3
S = 0 + 0.5 × 10 × 2²
S = 20 m
and now we find speed of the lighter piece that is
v² = v1² + 2 × a × S .................4
0 = v1² + 2 × -9.81 × (530-20)
v1² = 10006.2
v1 = 100.031 m/s
so now put all these in equation 1 we get
Mt Vt = M1 V1 + M2 V2
1500 × 20 = (1500 × 1/3 ) × 100.031 + (1500 × 2/3) + V2
30000 = 50015.5 + 1000 V2
V2 = -20.0155 m/s
so speed is -20.0155 m/s
that mean vertical component of second fragment will be move downward