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BaLLatris [955]
2 years ago
10

A box with sides of length 40 cm is made up of six pieces of concrete of thickness 5 mm. The inside of the box is filled with 10

0 moles of a diatomic ideal gas while the temperature outside the box is 30°C. At what rate is the temperature of the gas increasing when the gas is at -40°C? (The thermal conductivity of concrete is 0.33 W/(m×K).)a) 1.22 °C/s b) 1.45 °C/s c) 1.68 °C/s d) 2.13 °C/s e) 2.90 °C/s
Physics
1 answer:
Damm [24]2 years ago
4 0

Answer:

d)2.13 C s⁻¹

Explanation:

Rate of flow of heat through walls

=\frac{KA(T_2-T_1)}{d}

K = .33

A = 6 X .4 X .4 =0.96

T₂-T₁ = 30+40 = 70

d = 5 x 10⁻³

Put these data in the relation above

Rate of flow of heat

= \frac{.33\times.96\times70}{5\times10^{-3}}

= 4435.2 Js⁻¹

Specific heat of gas = 2.5 R = 20.785 J

Rise in temp = \frac{4435.2}{100\times20.785}

= 2.13 degree celsius.

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La masa de un camión es de
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Answer:

45000 kg and 45 tons  

Explanation:

The expression in kilograms and tons is shown below;

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3 0
2 years ago
Two particles are moving with positions given by x= 4t^2−2t and x= 6t^3+8t respectively.
Evgen [1.6K]

Explanation:

<em>a)Which of the two has uniform acceleration?</em>

Acceleration is the second derivative of position.  The acceleration of the first particle is:

x = 4t² − 2t

v = 8t − 2

a = 8

The acceleration of the second particle is:

x = 6t³ + 8t

v = 18t² + 8

a = 36t

The first particle has uniform acceleration.

<em>b)Which one is likely to come to rest at some time during its motion?</em>

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6 0
3 years ago
A ball is hit with a paddle, causing it to travel straight upward. It takes 2.90 s for the ball to reach its maximum height afte
zmey [24]

Answer:

A. 28.42 m/s

B. 41.21 m

Explanation:

From the question given above, the following data were obtained:

Time (t) to reach the maximum height = 2.90 s

Initial velocity (u) =?

Maximum height (h) =?

A. Determination of the initial velocity of the ball.

Time (t) to reach the maximum height = 2.90 s

Final velocity (v) = 0 m/s (at maximum height)

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u) =?

v = u – gt (since the ball is going against gravity)

0 = u – (9.8 × 2.9)

0 = u – 28.42

Collect like terms

0 + 28.42 = u

u = 28.42 m/s

Thus, the initial velocity of the ball is 28.42 m/s

B. Determination of the maximum height reached by the ball.

Final velocity (v) = 0 m/s (at maximum height)

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u) = 28.42 m/s

Maximum height (h) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = 28.42² – (2 × 9.8 × h)

0 = 807.6964 – 19.6h

Collect like terms

0 – 807.6964 = – 19.6h

– 807.6964 = – 19.6h

Divide both side by – 19.6

h = – 807.6964 / – 19.6

h = 41.21 m

Thus, the maximum height reached by the ball is 41.21 m

5 0
3 years ago
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