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n200080 [17]
2 years ago
14

A change in position is calleda ) speed b) distance ​

Physics
2 answers:
Irina-Kira [14]2 years ago
6 0
A its a its a its a its a
amid [387]2 years ago
6 0

Answer:

<h3>(b) distance </h3>

as well as displacement

Explanation:

<u>Distance</u> is a scalar quantity that refers to "how much ground an object has covered" during its motion.

<u>Displacement</u><u> </u>is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

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A cat has a mass of 4.6 kg. What is its weight on Earth's surface?
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<h3>✽ - - - - - - - - - - - - - - -  ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Earth's gravity is approximately 9.81

weight = mass x gravity

weight = 4.6 x 9.81

weight = 45.126

Answer is B. 45N

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4 0
3 years ago
Read 2 more answers
A visual display of data or information is a
Artist 52 [7]

A visual display of data or information is called a graph. There are many types of graphs. These can include pie graphs, bar graphs, and many more. Graphs are useful, because they show you visually data which is helpful to many. Hope this helped

4 0
3 years ago
Doe anyone get this ​
8_murik_8 [283]

Answer:

we know a = F/ M

Explanation:

  • 2 m/s²
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  • 9.25 m/ s²
  • 0.04 m/s²
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4 0
3 years ago
What is happening in the diagram?
pishuonlain [190]
In the diagram, the ship send sound(?) waves to the water, to determine if there is anything there. If there is something like a sunken ship shown in the diagram, the waves return in a shorter time hence you can understand if theres something or now. This is the principle of radars and sonars.
3 0
3 years ago
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A 100 kg box sits on an incline held at rest by a very thin rope attached to another mass hanging as shown. The force of frictio
MAVERICK [17]

If friction is acting along the plane upwards

then in this case we will have

For equilibrium of 100 kg box on inclined plane we have

mgsin\theta = F_f + T

also for other side of hanging mass we have

T = Mg = 50(9.8) = 490 N

now we have

100(9.8)sin\theta = 100 + 490

980sin\theta = 590

sin\theta = 0.602

\theta = 37 degree

In other case we can assume that friction will act along the plane downwards

so now in that case we will have

mgsin\theta + F_f = T

also we have

T = Mg = 50(9.8) N

now we have

100(9.8)sin\theta + 100 = 50(9.8)

980sin\theta + 100 = 490

980 sin\theta = 490 - 100

sin\theta = 0.397

\theta = 23.45 degree

<em>So the range of angle will be 23.45 degree to 37 degree</em>

6 0
3 years ago
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