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Ipatiy [6.2K]
2 years ago
5

Ehbwiuvuyevuhvwihbwijnwiubbs

Physics
1 answer:
skad [1K]2 years ago
5 0

Answer:

what this please be clear

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In a RLC circuit, a second capacitor is connected in parallel with the capacitor previously in the circuit. What is the effect o
Marrrta [24]

Answer:

<h2>Case i) if \omega L > \frac{1}{\omega c}</h2><h2>So initially if the circuit is inductive in nature then its net impedance will decrease after this</h2><h2>Case ii) if \omega L < \frac{1}{\omega c}</h2><h2>So initially if the circuit is capacitive in nature then its net impedance will increase after this</h2>

Explanation:

As we know that the impedance of the circuit is given as

z = \sqrt{(\omega L - \frac{1}{\omega c})^2 + R^2}

when we join another identical capacitor in parallel with previous capacitor in the circuit then we will have for parallel combination

c_{eq} = c_1 + c_2

so it is

c_{eq} = 2c

now we have

z = \sqrt{(\omega L - \frac{1}{2\omega c})^2 + R^2}

Case i) if \omega L > \frac{1}{\omega c}

So initially if the circuit is inductive in nature then its net impedance will decrease after this

Case ii) if \omega L < \frac{1}{\omega c}

So initially if the circuit is capacitive in nature then its net impedance will increase after this

7 0
3 years ago
If cake baking is compared to protein synthesis, what genetic structure would be analogous to the flour, sugar, and eggs?
galina1969 [7]
Mrnmrnamrnamrnamrnamrnamrnamrnamrnamrnamrna
7 0
3 years ago
A particle has 3 x 10^15 eV has a charge of 3uC is placed on a certain field.
Vinvika [58]

Answer:

no se porque xD jajjakajajjajajajjaj

8 0
3 years ago
Read 2 more answers
Air that enters the pleural space during inspiration but is unable to exit during expiration creates a condition called a. open
sertanlavr [38]

Answer:

The correct answer is d. tension pneumothorax.

Explanation:

The increasing build-up of air that is in the pleural space is what we call the tension pneumothorax and this happens due to the lung laceration that lets the air to flee inside the pleural space but it does not return.

4 0
3 years ago
A hot-air balloon plus cargo has a mass of 308 kg and a volume of 2910 m3 on a day when the outside air density is 1.22 kg/m3. T
lesya [120]

9514 1404 393

Answer:

  1.114 kg/m³

Explanation:

The total mass of the air in the balloon and the balloon + cargo will be the mass of the displaced air. If d is the density of the air in the balloon, then we have ...

  2910d +308 = 2910×1.22

Solving for d, we find ...

  2910d = 2919(1.22) -308

  d = 1.22 -308/2910

  d ≈ 1.114 . . . kg/m³

The density of the hot air is about 1.114 kg/m³.

6 0
3 years ago
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