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Rudik [331]
4 years ago
7

Nuclear energy is more harmful to the environment than a coal-fired power plant because it produces more mercury, air pollution,

and carbon dioxide. True False
Physics
1 answer:
krok68 [10]4 years ago
5 0
A nuclear power plant doesn't produce any of those things. It only produces electricity and heat. As long as there are no accidents, and the worn out nuclear fuel is handled properly, the nuclear plant isn't harmful to the environment at all.
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Calculate the Force of Gravity acting on an object that has a mass of 1.3 kg. The object is on Earth so use 9.8m/s2 for the acce
sweet-ann [11.9K]
To calculate the gravitational force acting on an object given the mass and the acceleration due to gravity, use the following formula.

Fg = m • g
Fg = 1.3 kg • 9.8 m/s^2
Fg = 12.74 N or about 12.7 N.

The solution is C. 12.7 N.
7 0
3 years ago
which of these chemical formulas represents two elements whose atoms have joined together with an ionic bond? A. O2 B. CaO C.NeN
cupoosta [38]
B: CaO
Because Calcium is a Metal and Oxygen is a Non-Metal. Ionic bonds are only formed with a Metal and a Non-Metal element.
3 0
3 years ago
The maximum wavelength that an electromagnetic wave can have and still eject electrons from a metal surface is 459 nm. What is t
spin [16.1K]

Answer:

2.7067 eV

Explanation:

h = Planck's constant = 6.626\times 10^{-34}\ m^2kg/s

c = Speed of light = 3\times 10^8\ m/s

\lambda_0 = Threshold wavelength = 459 nm

Work function is given by

W_0=\frac{hc}{\lambda_0}\\\Rightarrow W_0=\frac{6.626\times 10^{-34}\times 3\times 10^8}{459\times 10^{-9}}\\\Rightarrow W_0=4.33072\times 10^{-19}\ J

Converting to eV

1\ J=\frac{1}{1.6\times 10^{-19}}\ eV

4.33072\times 10^{-19}\ J=4.33072\times 10^{-19}\times \frac{1}{1.6\times 10^{-19}}\ eV=2.7067\ eV

The work function W0 of this metal is 2.7067 eV

4 0
3 years ago
The graph at the right shows the force needed to pull a bow back as the string is pulled further and further.
Sindrei [870]

A. 9 J

In a force-distance graph, the work done is equal to the area under the curve in the graph.

In this case, we need to extrapolate the value of the force when the distance is x=30 cm. We can easily do that by noticing that there is a direct proportionality between the force and the distance:

F=kx

where k is the slope of the line. We can find k, for instance chosing the point at x=5 cm and F=10 N:

k=\frac{F}{x}=\frac{10 N}{5 cm}=2 N/cm

And now we can calculate the work by calculating the area under the curve until x=30 cm, F=60 N:

W=\frac{1}{2} (height) (base)= \frac{1}{2}(60 N)(0.30 m)=9 J


B. 24.5 m/s

The mass of the arrow is m=30 g=0.03 kg. The kinetic energy of the arrow when it is released is equal to the work done by pulling back the bow for 30 cm:

W=K=\frac{1}{2}mv^2

where m is the mass of the arrow and v is its speed. By re-arranging the formula and using W=9 J, we find the speed:

v=\sqrt{\frac{2W}{m}}=\sqrt{\frac{2\cdot 9J}{0.03 kg}}=24.5 m/s

8 0
3 years ago
Mark and Leo are doing a experiment to see if rocks float. Leo uses a sedimentary rock. Does it float? Why or why not?
mrs_skeptik [129]
No because the rock isn't hollow it is hard from the inside out so it sinks because of its mass
8 0
3 years ago
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