Answer:
1.15 rad/s²
Explanation:
given,
angular speed of turntable = 45 rpm
=
=
time, t = 4.10 s
initial angular speed = 0 rad/s
angular acceleration.
Hence, the angular acceleration of the turntable is 1.15 rad/s²
Acceleration due to gravity is a constant -9.8 m/s until terminal velocity (maximum freefall speed) is reached.
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I hope it helped you
Explanation:
It is given that initially pressure of ideal gas is 4.00 atm and its temperature is 350 K. Let us assume that the final pressure is and final temperature is .
(a) We know that for a monoatomic gas, value of is \frac{5}{3}[/tex].
And, in case of adiabatic process,
= constant
also, PV = nRT
So, here = 350 K, , and
Hence,
= 267 K
Also, = 4.0 atm, , and
= 2.04 atm
Hence, for monoatomic gas final pressure is 2.04 atm and final temperature is 267 K.
(b) For diatomic gas, value of is \frac{7}{5}[/tex].
As, = constant
also, PV = nRT
= 350 K, , and
= 289 K
And, = 4.0 atm, , and
= 2.27 atm
Hence, for diatomic gas final pressure is 2.27 atm and final temperature is 289 K.
Answer:
It takes 28 days.
Explanation:
Hi there!
The half-life is the time at which the concentration of a substance is halved. For radon, it is 4 days. Then, after 4 days, the amount of radon present in the source will be 1/2 of its original concentration. After another 4 days, the concentration of radon will be half of the half of its original concentration, that is, 1/4 of the amount of radon originally present.
After another 4 days, the concentration will be halved again (1/4 /2 = 1/8) and after another 4 days, it will be halved again (1/8 / 2 = 1/16) and so on.
Then, after n half-lives, the concentration of radon will be reduced by a factor of 1/2ⁿ.
Then, to know how many half-lives it takes for the concentration of radon to be reduced to 1/128 of its original level, let´s solve this equation for n:
1/2ⁿ = 1/128
2ⁿ = 128
log 2ⁿ = log 128
n log 2 = log 128
n = log 128 / log 2
n = 7
After 7 half-lives, the concentration of radon will be reduced by 1/128. Since a half-life is 4 days, 7 half-lives will be (7 · 4) 28 days.