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ycow [4]
3 years ago
6

10.   Cumulus and stratus clouds belong to which cloud group?      

Physics
1 answer:
EastWind [94]3 years ago
5 0
Cumulus belongs to vertical clouds and status to low
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A 14.8-g piece of Styrofoam carries a net charge of -0.742 µC and is suspended in equilibrium above the center of a large, horiz
MAXImum [283]
Base on your question where a 14.8g of piece of Styrofoam carries a net charge of -0.742C and is suspended in equilibrium above the center of a large, horizontal sheet of plastic so the ask of the problem is to calculate  the charge per unit area on the plastic sheet. The answer would be 21.96
3 0
3 years ago
A 6.0 g marble is fired vertically upward using a spring gun. The spring must be compressed 9.4 cm if the marble is to just reac
RoseWind [281]

Answer:

a) \Delta U_{g} = 12.945\,J, b) \Delta U_{k} = 12.945\,J, c) k = 2930.059\,\frac{N}{m}

Explanation:

a) The change in the gravitational potential energy of the marble-Earth system is:

\Delta U_{g} = (0.06\,kg)\cdot \left(9.807\,\frac{m}{s^{2}}\right)\cdot (22\,m)

\Delta U_{g} = 12.945\,J

b) The change in the elastic potential energy of the spring is equal to the change in the gravitational potential energy, then:

\Delta U_{k} = 12.945\,J

c) The spring constant of the gun is:

\Delta U_{k} = \frac{1}{2} \cdot k \cdot x^{2}

k = \frac{2\cdot \Delta U_{k}}{x^{2}}

k = \frac{2\cdot (12.945\,J)}{(0.094\,m)^{2}}

k = 2930.059\,\frac{N}{m}

4 0
2 years ago
At which of the following temperature and pressure levels would a gas be most likely to follow the ideal gas law? A. 0 K and 100
bulgar [2K]
The Ideal Gas Law makes a few assumptions from the Kinetic-Molecular Theory. These assumptions make our work much easier but aren't true under all conditions. The assumptions are,

1) Particles of a gas have virtually no volume and are like single points.
2) Particles exhibit no attractions or repulsions between them.
3) Particles are in continuous, random motion.
4) Collisions between particles are elastic, meaning basically that when they collide, they don't lose any energy.
5) The average kinetic energy is the same for all gasses at a given temperature, regardless of the identity of the gas.

It's generally true that gasses are mostly empty space and their particles occupy very little volume. Gasses are usually far enough apart that they exhibit very little attractive or repulsive forces. When energetic, the gas particles are also in fairly continuous motion, and without other forces, the motion is basically random. Collisions absorb very little energy, and the average KE is pretty close.

Most of these assumptions are dependent on having gas particles very spread apart. When is that true? Think about the other gas laws to remember what properties are related to volume.

A gas with a low pressure and a high temperature will be spread out and therefore exhibit ideal properties.

So, in analyzing the four choices given, we look for low P and high T.

A is at absolute zero, which is pretty much impossible, and definitely does not describe a gas. We rule this out immediately.

B and D are at the same temperature (273 K, or 0 °C), but C is at 100 K, or -173 K. This is very cold, so we rule that out.

We move on to comparing the pressures of B and D. Remember, a low pressure means the particles are more spread out. B has P = 1 Pa, but D has 100 kPa. We need the same units to confirm. Based on our metric prefixes, we know that kPa is kilopascals, and is thus 1000 pascals. So, the pressure of D is five orders of magnitude greater! Thus, the answer is B.
6 0
3 years ago
Currents in dc transmission lines can be 100 A or higher. Some people are concerned that the electromagnetic fields from such li
lozanna [386]

Answer: 4.50*10^-6T (0.00000450071T)

Explanation: A current carrying conductor has been knowing to generate a specific amount of magnetic field.

This is given by the Bio-savart law (mathematical).

The Bio-savart law is a mathematical equation that gives the value of strength of the magnetic field created by a current carrying conductor.

B=(Uo* I) /2πr

Where

B= strength of magnetic field

Uo = magnetic permeability in free space = 1.257 *10^-6

r = distance between current carrying conductor and any reference point.

By doing the neccesary algebra, we have

B=(1.257 *10^-6 * 180)/ (2 * 3.142 * 8)

B= 2.2626 *10^-4 / 50.2857

B=4.5 * 10^-6T (0.00000450071T)

6 0
2 years ago
In nineteenth century, physical science was divided into discipline. . ​
dem82 [27]

Answer:

Here! Try this Website!: www.britannica.com › science › physical-science physical science | Definition, History, & Topics | Britannica. So you will learn a lot more about science, history, and topics about it!

8 0
1 year ago
Read 2 more answers
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