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ycow [4]
4 years ago
6

10.   Cumulus and stratus clouds belong to which cloud group?      

Physics
1 answer:
EastWind [94]4 years ago
5 0
Cumulus belongs to vertical clouds and status to low
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A distance-time graph indicates that an object moves 20 m in 10 s and then remains at rest for 20s. What is the average speed of
boyakko [2]

Answer:

v = 2 m/s

Explanation:

The object moves 20 m in 10 s initially. Then it remains at rest for 20 s. It is required to find the average speed of the object.

Fro 10 s it covers 20 m. For that time, speed is :

v=\dfrac{d}{t}\\\\v=\dfrac{20\ m}{10\ s}\\\\v=2\ m/s

For 20 s, it was at rest means distance covered is 0. So, speed is 0.

The average speed of the object is equal to the sum of speed for 10 s and for 20 s i.e.

v = 2 m/s + 0 = 2 m/s

So, the average speed of the object is 2 m/s.

3 0
3 years ago
4. An object moves in a circular path at a constant speed. Compare the direction of the object’s velocity and acceleration vecto
Vikentia [17]

Answer:

Option C

The vectors are perpendicular

Explanation:

Acceleration will be directed towards the center for uniform circular motion. Consequently, velocity of the object increases hence acceleration. The direction of velocity is tangent to its circular motion, therefore, tangential velocity vector is perpendicular to centripetal acceleration vector. Therefore, comparing the direction of the object, the vectors are perpendicular to each other.

4 0
3 years ago
A boat takes off from a dock at 2.5 m/s and speeds up at 4.2 m/s squared for six seconds how far has the most traveled
GaryK [48]

The boat's position x relative to its starting point x_0=0 is determined by

x=x_0+v_0t+\dfrac12at^2

where v_0 is its initial velocity, a is its acceleration, and t is time. After t=6\,\mathrm s, the boat has traveled

x=\left(2.5\,\dfrac{\mathrm m}{\mathrm s}\right)(6\,\mathrm s)+\dfrac12\left(4.2\,\dfrac{\mathrm m}{\mathrm s^2}\right)(6\,\mathrm s)^2

\implies x=91\,\mathrm m

3 0
3 years ago
Two metal plates 15mm apart have a potential difference of 750v between them. The force on a small charged sphere placed between
Romashka [77]

Answer:

50,000 V/m

Explanation:

The electric field between two charged metal plates is uniform.

The relationship between potential difference and electric field strength for a uniform field is given by the equation

\Delta V=Ed

where

\Delta V is the potential difference

E is the magnitude of the electric field

d is the  distance between the plates

In this problem, we have:

\Delta V=750 V is the potential difference between the plates

d = 15 mm = 0.015 m is the distance between the plates

Therefore, rearranging the equation we find the strength of the electric field:

E=\frac{\Delta V}{d}=\frac{750}{0.015}=50,000 V/m

6 0
4 years ago
true or false when taking a handoff you need to make sure you you reach out with your hands and grab the ball ​
astra-53 [7]

Answer:

i think False

Explanation:

8 0
3 years ago
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