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3 years ago

I need help getting started with number 8.

Physics

1 answer:

ratelena [41]3 years ago

4 0

In #8, the distance and the (magnitude of displacement) are equal, because he crawled in a straight line.

Displacement = (straight-line distance from start-point to end-point) in the direction from start to end, regardless of what route was actually followed.

Displacement = 5m, in the negative direction.

In #9 . . . distance will be the same. Displacement is going to be the same magnitude, but in the positive direction.

This is so simple that it's hard to talk about.

In #8, "What was the bug's distance ?". "Distance was 5 meters.". "What was the bug's displacement ?", "Displacement was 5 meters backwards."

In #9, What was the bug's distance ?". "Distance was 5 meters.". "What was the bug's displacement ?", "Displacement was 5 meters forward."

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When do net force is applied to a moving object it still comes to rest because of its inertia

Paraphin [41]

That is false for that.

6 0

3 years ago

A 13.0 kg wheel, essentially a thin hoop with radius 1.80 m, is rotating at 469 rev/min. It must be brought to a stop in 16.0 s.

Stella [2.4K]

Answer:

Explanation:

Given

mass of wheel m=13 kg

radius of wheel=1.8 m

N=469 rev/min

$\omega =\frac{2\pi \times 469}{60}=49.11 rad/s$

t=16 s

Angular deceleration in 16 s

$\omega =\omega _0+\alpha \cdot t$

$\alpha =\frac{\omega }{t}=\frac{49.11}{16}=3.069 rad/s^2$

Moment of Inertia $I=mr^2=13\times 1.8^2=42.12 kg-m^2$

Change in kinetic energy =Work done

Change in kinetic Energy $=\frac{I\omega ^2}{2}-\frac{I\omega _0^2}{2}$

$\Delta KE=\frac{42.12\times 49.11^2}{2}=50,792.34 J$

(a)Work done =50.79 kJ

(b)Average Power

$P_{avg}=\frac{E}{t}=\frac{50.792}{16}=3.174 kW$

7 0

3 years ago

YO CAN ANYONE DO THE BLANK COLUMN AND THE QUESTION PART RQ PLS!!

VikaD [51]

Answer:

stryo: 1

wood: 1

ice: 1

brick: 2

aluminum: 2.7

Explanation:

d= mass/ total volume

(fyi: for aluminum, they did the subtraction wrong to find the total volume. it is actually 5 or 5.00)

6 0

3 years ago

You are given two objects of identical size, one made of aluminum and the other of lead. You hang each object separately from a

ollegr [7]

Answer:

Explanation:

Volume of lead object = volume of aluminium object = V

mass of lead object > mass of aluminium object

When both the objects immersed in water, the buoyant force acting on both the objects.

Buoyant force = Volume immersed x density of water x gravity

As the volume of both the objects is same, so the buoyant force acting on both the objects is same.

So, weight in air of lead object is more than the weight in air of aluminium object.

7 0

3 years ago

Suppose a moving car has 2000 J of kinetic energy. If the carʹs speed doubles, how much kinetic energy would it then have?

Bond [772]

Answer:

option A

Explanation:

given,

Kinetic energy of the car = 2000 J

speed of the car is doubled

we know,

$KE_1 = \dfrac{1}{2}mv^2$

$2000= \dfrac{1}{2}mv^2$ ........(1)

now, speed of the car is doubled

v' = 2 v

$KE_2 = \dfrac{1}{2}mv'^2$

$KE_2 = \dfrac{1}{2}m(2v)^2$

from equation (1)

$KE_2 = 4\times \dfrac{1}{2}m(v)^2$

$KE_2 = 4\times 2000$

$KE_2 = 8000\ J$

Hence, the Kinetic energy would be equal to 8000 J.

The correct answer is option A.

8 0

3 years ago