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3 years ago

I need help getting started with number 8.

Physics

1 answer:

ratelena [41]3 years ago

4 0

In #8, the distance and the (magnitude of displacement) are equal, because he crawled in a straight line.

Displacement = (straight-line distance from start-point to end-point) in the direction from start to end, regardless of what route was actually followed.

Displacement = 5m, in the negative direction.

In #9 . . . distance will be the same. Displacement is going to be the same magnitude, but in the positive direction.

This is so simple that it's hard to talk about.

In #8, "What was the bug's distance ?". "Distance was 5 meters.". "What was the bug's displacement ?", "Displacement was 5 meters backwards."

In #9, What was the bug's distance ?". "Distance was 5 meters.". "What was the bug's displacement ?", "Displacement was 5 meters forward."

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The parallel plates in a capacitor, with a plate area of 7.10 cm2 and an air-filled separation of 2.20 mm, are charged by a 4.80

Lostsunrise [7]

Answer:

a)14.17V

b)32.8 x $10^-^1^2$ J

c)96.9x $10^-^1^2$ J

d) -64x $10^-^1^2$ J

Explanation:

Given:

Area 'A'=7.10cm² =>7.1 x $10^-^4$ m²

voltage ' $V_o$ '=4.8 volt

$d_o$ = 2.20mm => 2.2 x $10^-^3$ m

$d_1$ = 6.50mm => 6.5 x $10^-^3$ m

a) Capacitance $C_o$ before push is given by:

$C_o$ = εA/ $d_o$ => $\frac{(8.85*10^-^1^2)(7.1*10^-^4)}{2.2*10^-^3}$

$C_o$ = 2.85 x $10^-^1^2$ F

$q_o$ = $C_o$ $V_o$ => 2.85 x $10^-^1^2$ x 4.8

$q_o$ =1.37 x $10^-^1^1$ C

Capacitance $C_1$ after push is given by:

$C_1$ = εA/ $d_1$ => $\frac{(8.85*10^-^1^2)(7.1*10^-^4)}{6.5*10^-^3}$

$C_1$ = 9.66 x $10^-^1^3$ F

$q_o$ = $q_1$

$q_1$ = $C_1$ $V_1$

Therefore, the potential difference between the plates

$V_1$ = 1.37 x $10^-^1^1$ / 9.66 x $10^-^1^3$ =>14.17V

b) $U_i=\frac{1}{2}C_oV_o^2 => \frac{1}{2} (2.85*10^-^1^2)(4.8^2)$

$U_i=$ 32.8 x $10^-^1^2$ J

c) $U_f=\frac{1}{2}C_1V_1^2 => \frac{1}{2} (9.66*10^-^1^3)(14.17^2)$

$U_f$ = 96.9x $10^-^1^2$ J

d) the work required to separate the plates is given by:

workdone= $U_i$ - $U_f$ => 32.8 x $10^-^1^2$ J- 96.9x $10^-^1^2$ J

W≈ -64x $10^-^1^2$ J

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