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worty [1.4K]
3 years ago
7

If a man bought 1000N of potatoes in Russia and sold it in Africa for the same price, will he be in profit or loss? Explain your

answer with proper reason neglate the transportation cost
Physics
2 answers:
navik [9.2K]3 years ago
8 0

Answer:

profit because if the man sold them to africa hw must pay for it to send them to africa so it will voat him more.

almond37 [142]3 years ago
3 0

Answer:

Explanation:

if they are selling potatoes based on its weight, then it depends on the acceleration due to gravity(g) in the region

If g in africa > russia, then he will make a profit, since weight will be more,

if its < russia, then he will make a loss, i dont know thier actual values so you will have to find that out on your own

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Q 19.23: A proton is initially moving at 3.0 x 105 m/s. It moves 3.5 m in the direction of a uniform electric field of magnitude
DENIUS [597]

Answer:

The kinetic energy of the proton at the end of the motion is 1.425 x 10⁻¹⁶ J.

Explanation:

Given;

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distance moved by the proton, d = 3.5 m

electric field strength, E = 120 N/C

The kinetic energy of the proton at the end of the motion is calculated as follows.

Consider work-energy theorem;

W = ΔK.E

W =K.E_f - K.E_i

where;

K.Ef is the final kinetic energy

W is work done in moving the proton = F x d  = (EQ) x d = EQd

K.E_f =EQd + \frac{1}{2}m_pv_p_i^2

m_p \ is \ mass \ of \ proton = 1.673 \ \times \ 10^{-27} kg \\\\Q \ is \ charge \ of \ proton = 1.6 \times 10^{-19} C

K.E_f = 120\times 1.6 \times 10^{-19} \times 3.5   \ + \ \frac{1}{2}(1.673\times 10^{-27})(3\times 10^5)^2 \\\\

K.E_f = 6.72\times 10^{-17} \ + \ 7.53 \times 10^{-17} \\\\K.E_f = 14.25 \times 10^{-17} J\\\\K.E_f = 1.425\times 10^{-16} \ J

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3 0
3 years ago
A ball is thrown vertically upward. What is its acceleration right before it hits the earth?
Bezzdna [24]
<span>The entire time the ball is in the air, its acceleration is 9.8 m/s2 down provided this occurs on the surface of the Earth. Note that the acceleration can be either 9.8 m/s2 or -9.8 m/s2.
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A photon of wavelength 192 nm strikes an aluminum surface along a line perpendicular to the surface and releases a photoelectron
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Answer:

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KE=3.529\times10^{−27}\ J

5 0
3 years ago
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