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Evgen [1.6K]
4 years ago
14

Why does the band of stability curve upward at high atomic numbers? excess neutrons are required due to the repulsion between th

e protons. atoms with high atomic numbers have a large number of electrons orbiting the nucleus. this increased number of electrons requires a lot of extra mass in the nucleus to keep the electrons in their orbit?
Physics
1 answer:
ella [17]4 years ago
3 0
The band of stability curves upward at high atomic numbers due to the fact that excess of neutrons are required due to the repulsion between protons.

Atomic number is the number of protons. As the number of protons (atomic number) increase, the electrical repulsion force, due to the same sign of the protons inside the nucleus, becomes more dominant compared to the nuclear force attractions, then the nucleus needs more neutrons to gain stability.The presence of more neutrons decrease the density of protons which decreases the repulsion among them.


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How much time does it take a trucker to deliver his shipment 480 km away travelling at an average speed of 120 km/hr?​
kifflom [539]

Answer: time=4 hours

Explanation:

formula:

speed = \frac{distance}{time}

time = \frac{distance}{speed}

time= x

speed = 120km/hr

distance = 480 km

x = \frac{480 km}{120km/hr\\}

=\frac{48km*hr}{12km}

cut the zeros

and remove the signs

then

\frac{48}{12} = 4

therefore, time taken to deliver the shipment by trucker is 4 hours

8 0
3 years ago
A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.
Katen [24]

Answer:

9.4 m/s

Explanation:

The work-energy theorem states that the work done on an object is equal to the change in kinetic energy of the object.

So we can write:

W=K_f - K_i

where in this problem:

W = -36.733 J is the work performed on the car (negative because its direction is opposite to the motion of the car)

K_i = 66,120 J is the initial kinetic energy of the car

K_f is the final kinetic energy

Solving for Kf,

K_f = W+K_i = -36,733+66,120=29,387 J

The kinetic energy of the car can be also written as

K_f = \frac{1}{2}mv^2

where:

m = 661 kg is the mass of the car

v is its final speed

Solving, we find

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.4 m/s

8 0
3 years ago
In his famous experiment, Rutherford fired alpha particles at a thin gold film. Most of the alpha particles went through the fir
ale4655 [162]

Answer:

1. The nucleus is about 1/2 the size of the atom

Explanation:

Alpha particles are positive charge particles and they are bounced back by the nucleus because nucleus is also same size

Now in present experiment Rutherford found that very few alpha particles are bounced back along same path which shows that very small region inside the nucleus is having positive charge and rest part of the atom is empty.

Now if we found that half of the alpha particles are bounced back then it shows that size of the nucleus is very large now as compare to previous one because only nucleus can bounce back the alpha particles

so correct answer will be

1. The nucleus is about 1/2 the size of the atom

5 0
3 years ago
A Jack Rabbit hops 12.8 meters per second. How long would it take for him to hop 353 m? Round to the nearest tenth place. ​
adoni [48]

Time = Distance/speed

353/12.8 =27.57 seconds

4 0
3 years ago
Use the mass and density data to calculate the volume of corn syrup to the nearest tenth.
Nataly [62]
41.5 is the answer that i got. hope this helps!

4 0
3 years ago
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