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Assoli18 [71]
3 years ago
9

What is transferred when a wave hits the beach

Physics
1 answer:
Degger [83]3 years ago
8 0
A tsunami or a high tide wave
hoep this helped u!!
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In a drill during basketball practice, a player runs the length of the 30-meter court and back. The player does this three times
Sergeeva-Olga [200]

Answer:

0 m/s

Explanation:

Average velocity of an object is given by the net displacement divided by time taken. Displacement is equal to the shortest path covered by the object.

In this problem, a player runs the length of the 30-meter court and back. The player does this three times in 60 seconds.

As the player runs the court and returns to the original point. It would mean that the shortest path covered is 0.

Average velocity = displacement/time

v=0/30

v = 0 m/s

Hence, the correct option is (1).

6 0
3 years ago
Determine the angular speed, in rad/s of:
ryzh [129]

Answer:

Explanation:

A. The earth about its axis:

The earth makes one revolution in 24 hours. to know the number of revolutions per second it makes, we need to convert hours to seconds and the revolution to rad.

\frac{1 rev}{24hours}\times \frac{1 hr}{3600s}\times \frac{2\pi}{1}= 7.27 \times10^-5 rad/s

B. The minute hand of the clock makes one revolution in 60 minutes

To convert this to rad per second, we have

\frac{1 rev}{60mins}\times \frac{1 min}{60s}\times \frac{2\pi}{1}= 1.745 \times10^-3rad/s

C. The hour hand of  a clock completes one revolution in 12 hours

\frac{1 rev}{12hours}\times \frac{1 hr}{3600s}\times \frac{2\pi}{1}= 1.454 \times10^-4 rad/s

D. an egg beater turning at 300 rpm.

\frac{300 rev}{1minute}\times \frac{1 min}{60s}\times \frac{2\pi}{1}= 7.27 \times10^-5 rad/s=0.0218rad/s

6 0
2 years ago
What is gravity’s role in tides?
kotegsom [21]

The relationship between the masses of the Earth, moon and sun and their distances to each other play critical roles in affecting tides

6 0
3 years ago
Read 2 more answers
an object is placed 20cm from a converging lens. If the real image is formed 80cm from the object, what is the focal length of t
masya89 [10]

Explanation:

Here,

object distance(u)=20cm

image distance(v)=80cm-20cm=60cm

focal length(f)=?

we know ,

(1/f)=(1/v)+(1/u)

1/f = 1/60 + 1/20

1/f = (1+3)/60

60 =4f

f=15cm

8 0
2 years ago
A ball weighing 2.0 N falls through a distance of 4 m.
Naddik [55]

Answer:

This question is incomplete, a possible question would be to calculate the work done by the ball.

Work done = 8J

Explanation:

Work done by an object is calculated my multiplying the force by the distance.

The weight of this ball is 2.0N, which also represents the force exerted by the ball. The ball travels through a distance of 4m

Hence, work done = F × d

Work done = 2N × 4m

Work done = 8Nm or 8J

4 0
3 years ago
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