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4 years ago

40 POINTS EASY

1 answer:

7 0

We know, Mechanical Energy = K.E. + P.E.
As ball is at ground, P.E. would be zero. But as it is in motion, it must have some K.E. and that is:

K.E. = 1/2 mv²
K.E. = 1/2 * 1 * 2²
K.E. = 4/2
K.E. = 2 J

In short, Your Answer would be Option B

Hope this helps!

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A bowling ball has a mass of 6 kg. What happens to its momentum when its speed increases from 2 m/s to 4 m/s?

mash [69]

Answer:

B) The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s

Explanation:

The momentum of an object is given by the product between its mass (m) and its velocity (v):

$p=mv$

Let's apply this formula to calculate the initial momentum and final momentum of the ball:

- initial momentum:

$p_i = m v_i = (6 kg)(2 m/s)=12 kg m/s$

- Final momentum:

$p_f = m v_f = (6 kg)(4 m/s)=24 kg m/s$

So, the correct answer is

B) The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s

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3 years ago

Read 2 more answers

A golf club exerts an average horizontal force of 1005 N in the –x direction on a 453 grams golf ball that is initially at rest

adelina 88 [10]

Answer:

The impulse is 1.89 Ns and final velocity of the golf 4.17 $\frac{m}{s}$

Explanation:

Given:

Average force $F = 1005$ N

Contact time $t = 1.89 \times 10^{-3}$ sec

Mass of golf ball $m = 453 = 0.453$ kg

(a)

Impulse is given by,

$J = Ft$

$J = 1005 \times 1.89 \times 10^{-3}$

$J = 1.89$ Ns

(b)

For finding the final velocity,

$J = \Delta P$

$J = mv$

$1.89 = 0.453 v$

$v = 4.17 \frac{m}{s}$

Therefore, the impulse is 1.89 Ns and final velocity of the golf 4.17 $\frac{m}{s}$

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Answer:

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Explanation:

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4 years ago

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PSYCHO15rus [73]

Answer:

i think its true

Explanation:

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3 years ago