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Setler [38]
3 years ago
5

A 0.614mole sample of ideal gas at 12degree occupies a volume of 4.32.what is the pressure of the gas

Physics
1 answer:
Kaylis [27]3 years ago
3 0

Answer:

336.9520 atm

Explanation:

The Gas Equation is as follows;-

Pressure×Volume=Number of Moles × Universal Gas Constant ×Temperature(in Kelvin)

Given Parameters

Number of moles-0.614 mol

Temperature 12°C or 12+273.15 ie 285.15°F

Volume-4.32 L

Universal Gas Constant-8.314 J/mol·K

Pressure -?(in atm)

Plugging in all the values in the Gas Equation:-

Pressure=\frac{0.614 × 8.314× 285.15}{4.32}   atm

Pressure=336.9520 atm

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You work for an advertising company and have been hired to place a blimp above a football stadium. The angle of elevation from a
iogann1982 [59]

Answer:

a) tangent ; b) 153.88 yds ; c) No , less than or equal to 45° ; D) 45°

Explanation:

Given the following ;

From the triangle sketch :

Base length = 50 yards

Angle of elevation = 72°

a. Which trigonometric ratio would you use to calculate how high the blimp will be above the 50 yard line?

Using trigonometry :

The height of the blimp will be calculated using :

Tangent :

Tan θ = opposite / Adjacent

B.) How high above the ground is the blimp?

Using :

Tan θ = opposite / Adjacent

Θ = 72° ; adjacent = 52, opposite = height(h)

Tan 72° = h / 50

h = 3.0776835 * 50

h = 153.88 yds

C.) In order to be able to read the advertisement on the side of the blimp the highest the blimp can be is 150 feet. Will the fans be able to read the advertisement?

1 yard = 3 Feets

153.88 yards = 3 * 153.88

= 461.65 feets

No, because the height of the blimp is 461.65 Feets which is greater than 150 Feets.

To make viewing possible, the angle of elevation should be:

50 yards is equivalent to (3 * 50) = 150 feets

Max imum Height of blimp = 150 Feets

From pythagoras ;

Tanθ = 150 Feets / 150 Feets

Tanθ = 1

θ = tan^-1(1)

θ = 45°

To make viewing advertisement possible, angle of elevation should not exceed 45°

d.)If height of blimp is 150 Feets, then the exact angle of elevation will be 45°

5 0
3 years ago
An unknown number of identical light bulbs are connected to a 15 V battery in parallel. The current through the battery is 2 A.
zaharov [31]

Answer:

An unknown number of identical light bulbs are connected to a 15 V battery in parallel. The current through the battery is 2 A. If the light bulbs are connected to the battery in series, the current through the battery is 5 mA. How many bulbs are there?

3 bulbs are there from the analogy given above

Explanation:

7 0
3 years ago
A 50 W light bulb is plugged into a standard
wolverine [178]

Answer:

$1.26

Explanation:

Power =energy/ time

energy =powerxtime

energy =50x31x24=37200

=37.2kwh

1kwh =3.39

37.2kwh=3.39x37.2=126.108cent

=$1.26

8 0
3 years ago
A uniform bar has two small balls glued to its ends. The bar has length L and mass M, while the balls each have mass m and can b
vazorg [7]

Answer:

Explanation:

Length of bar = L

mass of bar = M

mass of each ball = m

Moment of inertia of the bar about its centre perpendicular to its plane is

I_{1}=\frac{ML^{2}}{12}

Moment of inertia of the two small balls about the centre of the bar perpendicular to its plane is

I_{2}=2\times m\times \frac{L^{2}}{4}

I_{2}=\frac{mL^{2}}{2}

Total moment of inertia of the system about the centre of the bar perpendicular to its plane is

I = I1 + I2

I=\frac{ML^{2}}{12}+\frac{mL^{2}}{2}

I=\frac{(M +6m)L^{2}}{12}

8 0
3 years ago
All of these are types of electromagnetic waves except for:
dimaraw [331]
C- Sigma Waves, This is what my teacher used to get us to remember https://www.youtube.com/watch?v=bjOGNVH3D4Y
3 0
3 years ago
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