Question

A 0.614mole sample of ideal gas at 12degree occupies a volume of 4.32.what is the pressure of the gas

Answer 1

Answer:

336.9520 atm

Explanation:

The Gas Equation is as follows;-

Pressure×Volume=Number of Moles × Universal Gas Constant ×Temperature(in Kelvin)

Given Parameters

Number of moles-0.614 mol

Temperature 12°C or 12+273.15 ie 285.15°F

Volume-4.32 L

Universal Gas Constant-8.314 J/mol·K

Pressure -?(in atm)

Plugging in all the values in the Gas Equation:-

Pressure=$\frac{0.614 × 8.314× 285.15}{4.32} atm$

Pressure=336.9520 atm