A 0.614mole sample of ideal gas at 12degree occupies a volume of 4.32.what is the pressure of the gas
1 answer:
Answer:
336.9520 atm
Explanation:
The Gas Equation is as follows;-
Pressure×Volume=Number of Moles × Universal Gas Constant ×Temperature(in Kelvin)
Given Parameters
Number of moles-0.614 mol
Temperature 12°C or 12+273.15 ie 285.15°F
Volume-4.32 L
Universal Gas Constant-8.314 J/mol·K
Pressure -?(in atm)
Plugging in all the values in the Gas Equation:-
Pressure=
Pressure=336.9520 atm
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The force between the molecules involved in the bond is 6. 426 *10^-11 Newton
<h3>How to determine the force</h3>
Using the formula:
F = K[q1 x q2]/D^2
where K is coulombs constant =9 *10 ^9 Nm^2/C^2.
q1 and q2 = charges = 1.60x10 -20C
d = distance between the charges = 2x10 -10 m
Substitute the values into the formula
F =
F =
F =
F = Newton
Thus, the force between the molecules involved in the bond is 6. 426 *10^-11 Newton
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