Answer:
19.8m/s
Explanation:
Given parameters:
Mass of the ball = 10kg
Height of the rail = 20m
Unknown:
Velocity at the bottom of the rail = ?
Solution:
The velocity at the bottom of the rail is its final velocity.
Using the appropriate motion equation, we can find this parameter;
V² = U² + 2gH
V is the final velocity
U is the initial velocity
g is the acceleration due to gravity
H is the height
the ball was rolled from rest, U = 0
V² = O² + 2 x 9.8 x 20
V = 19.8m/s
Answer: The amount of carbon-14 left after 10 years is 25 g
Explanation:
Formula used :

where,
a = amount of reactant left after n-half lives = ?
= Initial amount of the reactant = 100 g
n = number of half lives =
Putting values in above equation, we get:


Therefore, the amount of carbon-14 left after 10 years is 25 g
In a a cation-exchange resin, the outlet stream leaving the bed will contain
and
.
<h3>
What is cation-exchange resin?</h3>
- A resin or polymer that serves as a medium for ion exchange is known as an ion-exchange resin or cation-exchange resin.
- It is an insoluble matrix (or support structure) made from an organic polymer substrate, typically appearing as tiny (0.25-1.43 mm radius) microbeads that are white or yellowish in color.
- The process is known as cation-exchange resin because the beads are often porous, providing a wide surface area on and inside them where the trapping of ions takes place along with the concomitant release of other ions.
- cation-exchange resin comes in many different varieties. Polystyrene sulfonate is the main ingredient in most commercial resins. Many diverse separation, purification, and decontamination techniques use cation-exchange resin.
- The most typical examples are water filtration and water softening.
To learn more about cation-exchange resin with the given link
brainly.com/question/21052225
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Answer:
1109 g H₂O
Explanation:
2.2 pounds can be converted to grams using a conversion ratio:
(2.2lb)(453.592g/lb) = 997.9024 g C₅₇H₁₁₀O₆
The mass in grams is converted to moles using the molecular weight of tristearin (891.48 g/mol)
(997.9024 g)(mol/891.48g) = 1.119...mol C₅₇H₁₁₀O₆
The moles of C₅₇H₁₁₀O₆ can be related to the moles of water through the molar ratio:
(1.119mol C₅₇H₁₁₀O₆)(110 H₂O/2 C₅₇H₁₁₀O₆) = 61.545 mol H₂O
The mass of water is then calculated using the molecular weight (18.02 g/mol):
(61.545 mol)(18.02 g/mol) = 1109 g H₂O