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ollegr [7]
4 years ago
10

How does an ionic bond form

Chemistry
1 answer:
Harlamova29_29 [7]4 years ago
3 0
Ionic bonds are formed from the attraction of oppositely charged ions in a chemical compound
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Manganese (IV) nitride formula
stepan [7]

Answer:

Mg(NO3)2 is the formula of manganese (IV) nitride.

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3 years ago
DNA makes RNA, which makes<br> O ATP<br> O plasma<br> O lipids<br> O proteins<br> HELP ASAP PLEASE!
Akimi4 [234]

Answer:

It makes proteins ....................

6 0
3 years ago
How many atoms are in this formula PCl6 ?
Debora [2.8K]

The molecule is unstable and impossible to create the PCl_6

Only one way is that change the formula

  • PCl_6-

Lets look at structure(See attachment)

There are total 7atoms

  • P=1
  • Cl=6

4 0
2 years ago
What is true about the dilution of a solution?
Ulleksa [173]
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4 0
4 years ago
Go'=30.5 kJ/mol
makvit [3.9K]

Answer:

a) Keq = 4.5x10^-6

b) [oxaloacetate] = 9x10^-9 M

c) 23 oxaloacetate molecules

Explanation:

a) In the standard state we have to:

ΔGo = -R*T*ln(Keq) (eq.1)

ΔGo = 30.5 kJ/moles = 30500 J/moles

R = 8.314 J*K^-1*moles^-1

Clearing Keq:

Keq = e^(ΔGo/-R*T) = e^(30500/(-8.314*298)) = 4.5x10^-6

b) Keq = ([oxaloacetate]*[NADH])/([L-malate]*[NAD+])

4.5x10^-6 = ([oxaloacetate]/(0.20*10)

Clearing [oxaloacetate]:

[oxaloacetate] = 9x10^-9 M

c) the radius of the mitochondria is equal to:

r = 10^-5 dm

The volume of the mitochondria is:

V = (4/3)*pi*r^3 = (4/3)*pi*(10^-15)^3 = 4.18x10^-42 L

1 L of mitochondria contains 9x10^-9 M of oxaloacetate

Thus, 4.18x10^-42 L of mitochondria contains:

molecules of oxaloacetate = 4.18x10^-42 * 9x10^-9 * 6.023x10^23 = 2.27x10^-26 = 23 oxaloacetate molecules

3 0
4 years ago
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