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3 years ago

Explain how the sodium chloride works as a preservative

Chemistry

1 answer:

Olegator [25]3 years ago

8 0

Answer:

Eg:Salt...Essentially, water moves across a cell membrane to try to equalize the salinity or concentration of salt on both sides of the membrane. If you add enough salt, too much water will be removed from a cell for it to stay alive or reproduce. A high concentration of salt kills organisms that decay food and cause disease.

Explanation:

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From the list of substances, identify each as a strong acid, strong base, or neither a strong acid nor a strong base.

Dafna11 [192]

Answer:

HNO3 is a strong acid

HCl is also a strong acid

NaCl is a salt so it is neither a strong acid nor a strong base

Ca(OH)3 is a strong base

Explanation:

8 0

3 years ago

How many liters of gas will be in the closed reaction flask when 36.0L of ethane (C2H6) is allowed to react with 105.0L of oxyge

Ivan

Answer:- Volume of the gas in the flask after the reaction is 156.0 L.

Solution:- The balanced equation for the combustion of ethane is:

$2C_2H_6(g)+7O_2(g)\rightarrow 4CO_2(g)+6H_2O(g)$

From the balanced equation, ethane and oxygen react in 2:7 mol ratio or 2:7 volume ratio as we are assuming ideal behavior.

Let's see if any one of them is limiting by calculating the required volume of one for the other. Let's say we calculate required volume of oxygen for given 36.0 L of ethane as:

$36.0LC_2H_6(\frac{7LO_2}{2LC_2H_6})$

= 126 L $O_2$

126 L of oxygen are required to react completely with 36.0 L of ethane but only 105.0 L of oxygen are available, It means oxygen is limiting reactant.

let's calculate the volumes of each product gas formed for 105.0 L of oxygen as:

$105.0LO_2(\frac{4LCO_2}{7L O_2})$

= 60.0 L $CO_2$

Similarly, let's calculate the volume of water vapors formed:

$105.0L O_2(\frac{6L H_2O}{7L O_2})$

= 90.0 L $H_2O$

Since ethane is present in excess, the remaining volume of it would also be present in the flask.

Let's first calculate how many liters of it were used to react with 105.0 L of oxygen and then subtract them from given volume of ethane to know it's remaining volume:

$105.0LO_2(\frac{2LC_2H_6}{7LO_2})$

= 30.0 L $C_2H_6$

Excess volume of ethane = 36.0 L - 30.0 L = 6.0 L

Total volume of gas in the flask after reaction = 6.0 L + 60.0 L + 90.0 L = 156.0 L

Hence. the answer is 156.0 L.

5 0

3 years ago

What type of plate boundary causes a subduction zone?

Elenna [48]

The oceanic plate boundary :)

8 0

3 years ago

All substances taking part in a certain interaction are shown below: Butane is written followed by an addition sign followed by

OverLord2011 [107]

<span>The Law of Conservation of Mass simply states that the total amount of mass should not change in a chemical reaction that is isolated (no other objects can enter the reaction). The total mass of the reactants must be equal to the total mass of the products. Thus, t</span>he correct estimate of the amount of oxygen used in the interaction is the difference between 133 g and 29 g.

3 0

3 years ago

Read 2 more answers

what is the theoretical mass of xenon tetrafluoride that should form when 130.g of xenon is reacted with 100.g of F2? what is th

serg [7]

Answer:

The answer to your question is: 70.7 %

Explanation:

Equation

Xe + 2F₂ ⇒ XeF₄

limiting reactant = Xe

Xe is the limiting reactant because the ratio is:

theoretical = 131/ 76 = 1.72 g

experimental ratio = 130/100 = 1.3 the amount of F increased.

131.3 g of Xe ------------------ 207 g of XeF₄

130 g of Xe ------------------- x

x = (130 x 207) / 131.3

x = 205 g of XeF₄

% yield = 145 / 205 x 100

% yield = 70.7

5 0

3 years ago

Explain how the sodium chloride works as a preservative​

Explain how the sodium chloride works as a preservative