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3 years ago

Why is it unimportant to have the same powers of 10 we multiplying and dividing in Scientific Notation

Mathematics

2 answers:

nikdorinn [45]3 years ago

6 0

We only need to worry about the exponents

Darina [25.2K]3 years ago

3 0

You only to worry about the exponents and that’s it

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Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

3 years ago

QUICK QUESTION! PLEASE ANSWER FAST!

mr_godi [17]

A^2 + B^2 = C^2
7^2 + B^2 = 25^2
49 + B^2 = 625
-49 -49
B^2 = 576
Square root both sides
B = 24

4 0

3 years ago

Read 2 more answers

Pleaseeee help! I'm really confused.

seropon [69]

He will be making a right triangle with the legs being 24 x 45. The diagonal will be the hypotenuse of the triangle. To find the amount of fencing we need the perimeter of the triangle.
Use Pythagorean theorem to find the length of the hypotenuse.
a^2 + b^2 = c^2
24^2 + 45^2 = c^2
576 + 2025 = c^2
2601 = c^2
sqrt 2601 = c
c = 51
Adding the three lengths the total fencing needed is
51+24+45=120 meters

8 0

3 years ago

HELPPPP FIND THE AREA

GuDViN [60]

you can just split the figure in 2 separate figures and them add the areas:

area rec. 1:

3m×3m= 9m²

area rec. 2:

3m× (2m+3m)

= 3m×5m

=15m²

total area:

9m²+15m²= 24m²

5 0

2 years ago

Read 2 more answers

Can you help with this?

g100num [7]

Answer:

c or d

Step-by-step explanation:

good luck

hope this helps

need more answer? just follow me

and it will be nice if i get Brainliest!!

8 0

3 years ago