Answer: y=12
Step-by-step explanation:
10y+10=130
-10 -10
10y=120
—- ——
10. 10
Y=12
So what do u need help on??
Unless you're given the value of the variables, you can't really solve for anything. The only thing you can do is simplify.
<span>39+5h+4g-2h
The only like terms are 5h and -2h.
39 + 3h + 4g
This would be the simplified version.</span>
It's D because 140÷3.50 is 40
If you're using the app, try seeing this answer through your browser: brainly.com/question/3000586——————————
The answer is option
D) r < 5 or r > – 1.
I'm going to graph each inequality below on a number line.
A) r > 5 or r > – 1.

The result is found just by joining those two intervals together. Actually that compound inequality only implies
r > – 1which does not represent all real numbers.
—————
B) r > 5 or r < – 1.

Numbers between – 1 and 5 (including them) are not included in the union, so you don't have all real numbers represented there either.
—————
C) r < 5 or r < – 1.

Numbers that are greater or equal to 5 are not in the union. So it does not represent all real numbers.
—————
D) r < 5 or r > – 1.
Now
all real numbers are included in the union. So this is the right choice.
Answer:
option D) r < 5 or r > – 1.
I hope this helps. =)