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patriot [66]
3 years ago
7

does increasing the frquency of a wave also increse its wavelength?if not,how are these quantities related

Physics
1 answer:
IrinaK [193]3 years ago
3 0

Answer:

No.

Explanation:

No, increasing the frequency of a wave will not increase it's wavelength. Rather it will decrease the wavelength because frequency and wavelength are inversely related.

According to Formula:

v = f(lemda)

If the speed is kept constant to find the relationship between f and wavelength.

=> f is inversely propotional to wavelength.

Hope this helps!

Have a great day!

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Two charged concentric spherical shells have radii of 11.0 cm and 14.0 cm. The charge on the inner shell is 3.50 ✕ 10−8 C and th
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Answer:

The magnitude of the electric field are 2.38\times10^{4}\ N/C and 1.09\times10^{4}\ N/C

Explanation:

Given that,

Radius of inner shell = 11.0 cm

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Charge on inner shell q_{inn}=3.50\times10^{-8}\ C

Charge on outer shell q_{out}=1.60\times10^{-8}\ C

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E=\dfrac{kq}{r^2}

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r = distance

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E=\dfrac{9\times10^{9}\times3.50\times10^{-8}}{(11.5\times10^{-2})^2}

E=2.38\times10^{4}\ N/C

The total charge enclosed  by a radial distance 20.5 cm

The total charge is

q=q_{inn}+q_{out}

Put the value into the formula

q=3.50\times10^{-8}+1.60\times10^{-8}

q=5.1\times10^{-8}\ C

We need to calculate the magnitude of the electric field at r = 20.5 cm

Using formula of electric field

E=\dfrac{kq}{r^2}

Put the value into the formula

E=\dfrac{9\times10^{9}\times5.1\times10^{-8}}{(20.5\times10^{-2})^2}

E=1.09\times10^{4}\ N/C

Hence, The magnitude of the electric field are 2.38\times10^{4}\ N/C and 1.09\times10^{4}\ N/C

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