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ss7ja [257]
3 years ago
9

A box on a table has these forces acting on it

Physics
1 answer:
umka21 [38]3 years ago
8 0

Answer:

greater than 10 n

Explanation:

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Un carro parte del reposo y acelera uniformemente a 4.0 m / s^2 durante 5.0 s. A continuación, mantiene la velocidad que alcanzó
Arada [10]

Answer:

Average speed of the car = 16.53 m.s

Explanation:

For first 5 seconds:

As the car starts from rest, so the initial speed of the car, u=0

Acceleration, a= 4 m/s^2

So, the final speed (speed at time, t=5 second)

v=u+at

v=0 + 4 x 5 = 20 m/s

Distance covered,

s=ut+\frac 1 2 a t^2 \\\\s=0+\frac 1 2 \times 4 \times 5^2

s=50 m

As the car maintained the constant speed of 20 m/s for the next 10 seconds.

Distance traveled in 10 seconds, d=20 x 10 =200 m

For the last 4 seconds:

The car slows down at the rate of 2.0 m / s ^ 2 from the speed of 20 m/s.

As the car slows down, so the acceleration will be negative, i.e a=-2 m/s^2

s=ut+\frac 12 at^2 \\\\s=20\times 4 +\frac 12 (-2)4^2

s=80-16=64 m.

Considering all three cases, the total distance covered=

=50+200+64=314 m

Total time= 5+10+4=19 s

So, the averate peed= Totat distance covered / total time taken

=314/19=16.53 m/s

6 0
3 years ago
Calculate the tension on the rope.<br> A. 57.89 N<br> B. 32.73 N<br> C. 69.84 N<br> D. 12.55 N
Ratling [72]

Hi there!

\large\boxed{\text{B. 32.73N}}

To calculate the tension, we must calculate the acceleration of the system.

Begin with a summation of forces:

∑F = -M₁gsinФ + T - T + M₂g

Simplify and solve for acceleration: (Tensions cancel out)

a = \frac{-M_1gsin\theta + T - T + M_2g}{M_1+M_2}

Plug in values. Let g = 10 m/s²

a = \frac{-3(10)(sin30)+8(10)}{3+8} = 5.91 m/s^{2}

Now, to find tension, let's sum up the forces acting on ONE block. For simplicity, we can look at the hanging block:

∑F = -T + W

ma = -T + W

Rearrange to solve for T:

T = W - ma

We know the acceleration, so plug in the values:

T = (8)(10) - (8)(5.91) = 32.73 N

3 0
3 years ago
Oil (SAE 30) at 15.6 oC flows steadily between fixed, horizontal, parallel plates. The pressure drop per unit length along the c
solong [7]

Answer:

q = 0.0003649123 m²/s = (3.65 × 10⁻⁴) m²/s

Explanation:

For laminar flow between two parallel horizontal plates, the volumetric flow per metre of width is given as

q = (2h³/3μ) (ΔP/L)

h = hydraulic depth = 4mm/2 = 2mm = 0.002 m

μ = viscosity of oil (SAE 30) at 15.6°C = 0.38 Pa.s

(ΔP/L) = 26 KPa/m = 26000 Pa/m

q = (2h³/3μ) (ΔP/L)

q = (26000) × (2(0.002³)/(3×0.38))

q = 0.0003649123 m²/s = (3.65 × 10⁻⁴) m²/s

5 0
3 years ago
Read 2 more answers
•. Parking orbit is -
notsponge [240]

Answer:

Parking orbit is -

a. The path along which a plane travels

b. Orbit of a polar satellite

c. Orbit of geostationary satellite

d. Orbit of the earth.

Explanation:

7 0
3 years ago
Read 2 more answers
the total mass of the sun is about 2×1030 kg, of which about 76 % was hydrogen when the sun formed. however, only about 14 % of
likoan [24]

The total amount of mass in the Sun is 2.0 x 10^30 kg, 5% of whig is hydrogen, and 13% of which becomes available for fusion. Thus, the total mass of hydrogen available for fusion over the Sun's lifetime is simply 13% of 75% of the total mass of the Sun or:

2.0 x 10^30 kg x .75 x .13

=<u> 1.95 x 10^29 kg</u>

<u />

Nuclear fusion occurs only in the core of the sun where temperature pressure and density are highest. The photosphere can be seen with visible light telescopes, the chromosphere with ultraviolet telescopes, and the corona most easily with X-ray telescopes.

The Sun is a typical star and also the closest star to the Earth. It is composed of 73% hydrogen, 25% helium, and 2% other elements. Since the gravitational pull of the sun on the earth is the centripetal force that causes the earth to move in a circular motion around the sun, we can use Newton's law of universal gravitation to find the mass of the sun without visiting it.

Learn more about The temperature here:- brainly.com/question/24746268

#SPJ4

3 0
1 year ago
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