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Kryger [21]
3 years ago
6

Which of the following equations represents Ohm’s Law? Select all that apply.

Physics
2 answers:
Vera_Pavlovna [14]3 years ago
6 0

Answer : The correct options are, V=IR, I=V/R  and R=V/I

Explanation :

Ohm's law : It is defined as an electric current is directly proportional to voltage and inversely proportional to resistance.

Formula of Ohm's law :

V=I\times R

Or,

R=\frac{V}{I}

or,

I=\frac{V}{R}

where,

R = resistance of a circuit

V = voltage of circuit

I = current flowing in a circuit

Hence, the correct options are, V=IR, I=V/R  and R=V/I

yaroslaw [1]3 years ago
3 0

The first three choices are nonsense.

The last three choices are alternative statements of Ohm's law:

R = V / I

V = I · R

I = V / R

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Answer:

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Explanation:

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Two blocks are connected by a light weight, flexible cord that passes over a frictionless pulley.Ifm1=2 kg and m2 = 3 kg, and bl
Vera_Pavlovna [14]

Answer:

t = 1.41 sec.

Explanation:

If we assume that the acceleration of the blocks is constant, we can apply any of the kinematic equations to get the time since the block 2 was released till it reached the floor.

First, we need to find the value of  acceleration, which is the same for both blocks.

If we take as our system both blocks, and think about the pulley as redirecting the force simply (as tension in the strings behave like internal forces) , we can apply Newton's 2nd Law, as they were moving along the same axis, aiming at opposite directions, as follows:

F = m₂*g - m₁*g = (m₁+m₂)*a (we choose as positive the direction of the acceleration, will be the one defined by the larger mass, in this case m₂)

⇒ a = (\frac{(m₂-m₁)}({m₁+m₂} * g = g/5 m/s²

Once we got the value of a, we can use for instance this kinematic equation, and solve for t:

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6 0
3 years ago
Argument changes meaning because of an ambiguous word or phrase.
Virty [35]
I think the answer is D
7 0
3 years ago
A wheel with a tire mounted on it rotates at the constant rate of 2.73 revolutions per second. Find the radial acceleration of a
Lostsunrise [7]

Answer:

110.9 m/s²

Explanation:

Given:

Distance of the tack from the rotational axis (r) = 37.7 cm

Constant rate of rotation (N) = 2.73 revolutions per second

Now, we know that,

1 revolution = 2\pi radians

So, 2.73 revolutions = 2.73\times 2\pi=17.153\ radians

Therefore, the angular velocity of the tack is, \omega=17.153\ rad/s

Now, radial acceleration of the tack is given as:

a_r=\omega^2 r

Plug in the given values and solve for a_r. This gives,

a_r=(17.153\ rad/s)^2\times 37.7\ cm\\a_r=294.225\times 37.7\ cm/s^2\\a_r=11092.28\ cm/s^2\\a_r=110.9\ m/s^2\ \ \ \ \ \ \ [1\ cm = 0.01\ m]

Therefore, the radial acceleration of the tack is 110.9 m/s².

4 0
3 years ago
Anyone know how to do this ?
soldi70 [24.7K]
Not really but I need points lol
3 0
3 years ago
Read 2 more answers
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