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Kryger [21]
3 years ago
6

Which of the following equations represents Ohm’s Law? Select all that apply.

Physics
2 answers:
Vera_Pavlovna [14]3 years ago
6 0

Answer : The correct options are, V=IR, I=V/R  and R=V/I

Explanation :

Ohm's law : It is defined as an electric current is directly proportional to voltage and inversely proportional to resistance.

Formula of Ohm's law :

V=I\times R

Or,

R=\frac{V}{I}

or,

I=\frac{V}{R}

where,

R = resistance of a circuit

V = voltage of circuit

I = current flowing in a circuit

Hence, the correct options are, V=IR, I=V/R  and R=V/I

yaroslaw [1]3 years ago
3 0

The first three choices are nonsense.

The last three choices are alternative statements of Ohm's law:

R = V / I

V = I · R

I = V / R

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The magnitude of the magnetic force acting on the charge is 2.34×10⁻³ N.

<h3>What is magnetic force?</h3>

A magnetic force is the force that act in a magnetic field.

To calculate the magnetic force, we use the formula below.

Formula:

  • F = qvB.........Equation 1

Where:

  • F = magnetic force
  • q = point charge
  • v = Velocity of the the charge
  • B = Field strength

From the question,

Given:

  • q = 5.0×10⁻⁷ C
  • v = 2.6×10⁵ m/s
  • B = 1.8×10⁻² T

Substitute these values into equation 2

  • F = (5.0×10⁻⁷)(2.6×10⁵)(1.8×10⁻²)
  • F = 23.4×10⁻⁴
  • F = 2.34×10⁻³ N

Hence, the magnitude of the magnetic force acting on the charge is 2.34×10⁻³ N.

Learn more about magnetic force here: brainly.com/question/2279150

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2 years ago
Which organelle is most like a factory delivery driver?
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Marina CMI [18]

Answer:

(a) \vec{J}=176.4\frac{kg*m}{s} \hat{j}

(b) F=2125.30N

Explanation:

(a) According to the law of conservation of energy, the potential energy of the person at 0.40 m is equal to its kinetic energy before the colision with the floor:

\Delta U=\Delta K\\mgh=\frac{mv^2}{2}\\v=\sqrt{2gh}\\v=\sqrt{2(9.8\frac{m}{s^2})(0.40m)}\\v=2.8\frac{m}{s}

This is the initial velocity in the negative y-direction. Impulse is given by:

\vec{J}=\Delta \vec{p}\\\vec{J}=m\vec{v_f}-m\vec{v_i}\\\vec{J}=63kg(0 \hat{j})-63kg(-2.8\frac{m}{s} \hat{j})\\\vec{J}=176.4\frac{kg*m}{s} \hat{j}

(b) The average force is:

F=\frac{J}{\Delta t}\\F=\frac{176.4\frac{kg*m}{s}}{0.083s}\\F=2125.30N

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3 years ago
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